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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
Topic 1: SQL Functions	- Single-row functions 1. Character, numeric, date functions - Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions
Topic 2: Relational Database Concepts	- Data types and database objects overview - Tables, rows, columns, and relational model basics
Topic 3: SQL Retrieval	- SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting - Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS
Topic 4: Subqueries and Advanced SQL	- Correlated subqueries and nested queries - Single-row and multi-row subqueries
Topic 5: Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints

>> Exam 1z0-071 Topics <<

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Oracle Database SQL Sample Questions (Q138-Q143):

NEW QUESTION # 138
Examine the data in the CUST_NAME column of the CUSTOMERS table:
CUST_NAME
---------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikkilineni
Julia Nayer
You want to display the CUST_NAME values where the last name starts with Mc or MC.
Which two WHERE clauses give the required result?

A. WHERE INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ') + 1)) IN ('MC%','Mc%')
B. WHERE SUBSTR(cust_name, INSTR(cust_name,' ') + 1) LIKE 'Mc%' OR 'MC%'
C. WHERE SUBSTR(cust_name, INSTR(cust_name,' ') + 1) LIKE 'Mc%'
D. WHERE UPPER(SUBSTR(cust_name, INSTR(cust_name,' ') + 1)) LIKE UPPER('MC%')
E. WHERE INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ') + 1)) LIKE 'Mc%'

Answer: D,E

NEW QUESTION # 139
View the exhibit and examine the structures of the EMPLOYEES and DEPARTMENTS tables.

You want to update EMPLOYEES table as follows:
Update only those employees who work in Boston or Seattle (locations 2900 and 2700).
Set department_id for these employees to the department_id corresponding to London (location_id 2100).
Set the employees' salary in location_id 2100 to 1.1 times the average salary of their department.
Set the employees' commission in location_id 2100 to 1.5 times the average commission of their department.
You issue the following command:

What is outcome?

A. It executes successfully but does not give the desired update.
B. It executes successfully and gives the desired update.
C. It generates an error because a subquery cannot have a join condition in a UPDATE statement.
D. It generates an error because multiple columns (SALARY, COMMISSION) cannot be specified together in an UPDATE statement.

Answer: A

NEW QUESTION # 140
Which two statements are true about conditional INSERT ALL?

A. Each row returned by the subquery can be inserted into only a single target table.
B. A single WHEN condition can be used for multiple INTO clauses.
C. Each WHEN condition is tested for each row returned by the subquery.
D. The total number of rows inserted is always equal to the number of rows returned by the subquery
E. It cannot have an ELSE clause.

Answer: C,D

NEW QUESTION # 141
Which three are true about scalar subquery expressions? (Choose three.)

A. They can be nested.
B. A scalar subquery expression that returns zero rows evaluates to zero.
C. They can be used as default values for columns in a CREATE TABLE statement.
D. A scalar subquery expression that returns zero rows evaluates to NULL.
E. They cannot be used in the VALUES clause of an INSERT statement.
F. They cannot be used in GROUP BY clauses.

Answer: A,C,D

Explanation:
https://docs.oracle.com/cd/B12037_01/server.101/b10759/expressions010.htm

NEW QUESTION # 142
See the Exhibit and examine the structure of the PROMOTIONS table:

Using the PROMOTIONS table,
you need to find out the average cost for all promos in the range $0-2000 and $2000-5000 in category A.
You issue the following SQL statements:

What would be the outcome?

A. It generates an error because CASE cannot be used with group functions.
B. It generates an error because multiple conditions cannot be specified for the WHEN clause.
C. It executes successfully and gives the required result.
D. It generates an error because NULL cannot be specified as a return value.

Answer: C

Explanation:
CASE Expression
Facilitates conditional inquiries by doing the work of an IF-THEN-ELSE statement:
CASE expr WHEN comparison_expr1 THEN return_expr1
[WHEN comparison_expr2 THEN return_expr2
WHEN comparison_exprn THEN return_exprn
ELSE else_expr]
END

NEW QUESTION # 143
......

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