App-Development-with-Swift-Certified-User Testking & App-Development-with-Swift-Certified-User Testfagen

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Apple App-Development-with-Swift-Certified-User Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|
| Topic 1: App Design and Best Practices | 15% | - Code organization
- 1. Readability and maintainability
- User experience principles
- 1. Human Interface Guidelines
|
| Topic 2: Development Environment | 15% | - Debugging techniques
- 1. Logging and error resolution
- 2. Breakpoints and step-through execution
- Building and running apps
- 1. iOS Simulator usage
- 2. Deploying to physical devices
- Xcode interface and tools
- 1. Navigating project structure
- 2. Using documentation and help resources
|
| Topic 3: SwiftUI Basics | 25% | - State management
- 1. Basic state properties
- 2. Data flow between views
- Layout and navigation
- 1. Navigation patterns and presentation
- 2. Stacks, grids and alignment
- Views and controls
- 1. Built-in UI components
- 2. Modifiers and styling
|
| Topic 4: Data Handling and Logic | 15% | - Basic data processing
- 1. Working with strings and numbers
- Error handling
- 1. Do-catch and optional handling
|
| Topic 5: Swift Programming Fundamentals | 30% | - Control flow
- 1. Conditional statements and loops
- 2. Switch statements and pattern matching
- Basic types and operators
- 1. Data types, type inference and casting
- 2. Constants and variables
- Structures and classes
- 1. Properties, methods and initializers
- Collection types
- 1. Arrays, dictionaries and sets
- Functions
- 1. Parameter customization and default values
- 2. Definition, parameters and return values
|
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App-Development-with-Swift-Certified-User Testfagen & App-Development-with-Swift-Certified-User Tests
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Apple App Development with Swift Certified User Exam App-Development-with-Swift-Certified-User Prüfungsfragen mit Lösungen (Q14-Q19):
14. Frage
Review the code snippet.

The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
- A. Change the type of quantity from int to Double .
- B. Change the initial value of totalCost from o to 0.0.
- C. Chang the type of unitPrice from Double to Int.
- D. Change totalCost from let to var to make it mutable.
- E. Change shipping from let to var to make it mutable.
Antwort: A,D
Begründung:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
15. Frage
Review the code.
struct ContentView: View {
let fruits = [ " Apple " , " Banana " , " Kiwi " ]
var body: some View {
List(fruits, id: \.self) { fruit in
Text(fruit)
.font(.headline)
.padding()
}
}
}
Which of the following statements is true about the code?
- A. The List view is using the fruits array to display the contents as individual rows.
- B. The id: \.self in the List view should be rewritten as id: /self
- C. KeyPaths are used here to extract the font and padding properties dynamically.
- D. The id: \.self in the List view is not necessary and may be omitted.
Antwort: A
Begründung:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question belongs to View Building with SwiftUI , especially the domain covering List Views to iterate through collections . In the code, fruits is an array of strings, and the List initializer is being used to create one row for each item in that collection. Apple's SwiftUI documentation explains that List can present rows from a collection of data, and when the data elements are not supplied through a type that already provides identity, you can provide an id key path so SwiftUI can uniquely identify each row. Here, id: \.self tells SwiftUI to use each string value itself as the identifier.
Option D is therefore the correct statement because the List is clearly rendering the contents of the fruits array as separate rows, and each row shows a Text(fruit) view. Apple's app development tutorials describe List as a container view that displays rows of data arranged in a single scrollable column, which matches exactly what this code is doing.
Option A is false because for an array of String values in this form, id: \.self is used to identify each row.
Option B is false because the key path is not related to .font(.headline) or .padding(); those are standard view modifiers, not dynamic property extraction in this example. Option C is false because Swift key-path syntax uses a backslash, as in \.self, not /self. Apple's KeyPath documentation shows that Swift key paths use the backslash form.
16. Frage
Review the code snippet.

What is the output from each print statement?
Antwort:
Begründung:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
17. Frage
Review the code snippet.

Which statement completes the code snippet so that:
* The lastReleaseDate remains the same when nextApplePhone.releaseDate is nil.
* The lastReleaseDate updates to the nextApplePhone.releaseDate when nextApplePhone.releaseDate is NOT nil.
- A. nextApplePhone.releaseDate! : lastReleaseDate
- B. lastReleaseDate : nextApplePhone.releaseDate
- C. nextApplePhone.releaseDate : lastReleaseDate
- D. lastReleaseDate : nextApplcPhone.rcleaseDate!
Antwort: A
Begründung:
This question is from Swift Programming Language , especially the domains for Optional types , safe and unsafe unwrapping , and control flow . The code uses the ternary conditional operator :
nextApplePhone.releaseDate != nil ? _____
In Swift, the ternary operator follows this structure:
condition ? valueIfTrue : valueIfFalse
So if nextApplePhone.releaseDate != nil is true, the expression must return the new release date. If it is false, it must keep lastReleaseDate unchanged. That means the missing part must be:
nextApplePhone.releaseDate! : lastReleaseDate
which is option D .
This works because nextApplePhone.releaseDate is declared as String?, so it is an optional. Once the condition confirms it is not nil, the code force-unwraps it with ! to access the underlying String value. If the optional is nil, the expression returns lastReleaseDate instead. Apple's Swift documentation describes the ternary conditional operator as a shortcut for choosing one of two expressions based on a condition, and it explains that force unwrapping with ! accesses an optional's wrapped value when you know it is not nil.
The other options are incorrect because they reverse the true/false logic, omit the needed unwrap, or contain invalid identifiers. Therefore, the correct completion is D .
18. Frage
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
- A. capitalCities[ " Rome " ] = " Italy "
- B. capitalCities.updateValue( " Rome " , forKey: " Italy " )
- C. capitalCities[ " Italy " ] = " Rome "
- D. capitalCities.append([ " Italy " : " Rome " ])
- E. capitalCities = capitalCities + [ " Italy " : " Rome " ]
Antwort: B,C
Begründung:
Comprehensive and Detailed Explanation From App Development with Swift domains:
This question falls under Swift Programming Language , specifically the domain for managing data using collection types , with emphasis on dictionaries . In Swift, a dictionary stores data as key-value pairs , so in this example the country name is the key and the capital city is the value. To add a new entry, Swift supports two standard approaches. The first is subscript assignment , which is shown in option C : capitalCities[ " Italy " ] = " Rome " . Apple's documentation explains that you can add a key-value pair to a dictionary by assigning a value for a new key through the dictionary subscript.
The second correct approach is option E : capitalCities.updateValue( " Rome " , forKey: " Italy " ). Apple documents that updateValue(_:forKey:) updates the value for an existing key, or adds a new key-value pair if the key does not already exist . That makes it equally valid for inserting " Italy " : " Rome " into the dictionary.
The incorrect options fail for different reasons. A reverses the key and value, making " Rome " the key and " Italy " the value. B is wrong because append is used with arrays, not dictionaries. D is not the standard valid insertion syntax for Swift dictionaries in this context; Swift's documented mutation approaches here are subscript assignment and updateValue. Therefore, the two correct answers are C and E .
19. Frage
......
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