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Oracle Database SQL Sample Questions (Q174-Q179):

NEW QUESTION # 174
Examine the description of the ORDERS table:

Which three statements execute successfully?

A. SELECT order_ id, order_ data FROM orders
UNION ALL
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY order_ id;
B. SELECT * FROM orders ORDER BY order_ id
INTERSEOT
SELECT * FROM invoices ORDER BY invoice_ id;
C. SELECT * FROM orders
MINUS
SELECT * FROM INVOICES ORDER BY 1
D. SELECT * FROM orders ORDER BY order_ id
UNION
SELECT * FROM invoices;
E. (SELECT * FROM orders
UNION ALL
SELECT* FROM invoices) ORDER BY order _id;
F. SELECT order_ id, invoice_ data order_ date FROM orders
MINUS
SELECT invoice_ id, invoice_ data FROM invoices ORDER BY invoice_ id;
G. SELECE order _id, order _ date FRON orders
LNTERSECT
SELECT invoice_ id, invoice_ id, order_ date FROM orders

Answer: A,D,E

Explanation:
In Oracle SQL, set operations like UNION, UNION ALL, INTERSECT, and MINUS can be used to combine results from different queries:
* Option A:
* Combining results using UNION ALL followed by ORDER BY will execute successfully because UNION ALL allows duplicate rows and ORDER BY can be used to sort the combined result set.
* Option E:
* Similar to option A, UNION ALL combines all rows from the two selects and allows ordering of the results.
* Option G:
* UNION combines the results from two queries and removes duplicates, and ORDER BY can be used to sort the final result set.
Options B, C, D, and F are incorrect because:
* Option B: You cannot intersect different columns (ORDER_ID with INVOICE_ID).
* Option C: Incorrect column names and syntax with ORDER BY.
* Option D: ORDER BY cannot be used before a set operator like INTERSECT.
* Option F: ORDER BY cannot be used directly after a MINUS operator without wrapping the MINUS operation in a subquery.

NEW QUESTION # 175
View the Exhibit and examine the data in the EMPLOYEES table.
Exhibit

You want to generate a report showing the total compensation paid to each employee to date.
You issue the following query:

What is the outcome?

A. It executes successfully but does not give the correct output.
B. IT executes successfully and gives the correct output.
C. It generates an error because the usage of the ROUNDfunction in the expression is not valid.
D. It generates an error because the alias is not valid.
E. It generates an error because the concatenation operator can be used to combine only two items.

Answer: A

NEW QUESTION # 176
Which statement is true regarding external tables?

A. The CREATE TABLE AS SELECT statement can be used to unload data into regular table in the database from an external table.
B. The default REJECT LIMIT for external tables is UNLIMITED.
C. The data and metadata for an external table are stored outside the database.
D. ORACLE_LOADER and ORACLE_DATAPUMP have exactly the same functionality when used with an external table.

Answer: A

Explanation:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm

NEW QUESTION # 177
View the Exhibit and examine the structure of the BOOKStable.

The BOOKS table contains details of 100 books.
Examine the commands executed and their outcome:

Which statement is true?

A. Both ROLLBACKcommands restore the 100 rows that were deleted.
B. The first rollback restores the 101 rows that were deleted and the second rollback causes the row was inserted to be deleted and commits the changes.
C. The first rollback restores the 100 rows that were deleted and the second rollback commits only the changes.
D. Both ROLLBACKcommands restore the 101 rows that were deleted.

Answer: B

NEW QUESTION # 178
Examine the data in the COLORS table:

Examine the data in the BRICKS table:

Which two queries return all the rows from COLORS?

A. SELECT
FROM bricks b
FULL JOIN colors C
ON b. color rgb _ hex_ value = c. rgb _hex_ value;
B. SELECT.
FROM bricks b
RIGHT JOIN colors c
ON b. color _rgb_ hex_ value = c. rgb hex_ value;
C. SELECT *
EROM bricks | b
JOIN colors C
ON b. color_ rgb_ hex_ value =c. rgb _hex value;
D. SELECT
EROM colors C
LEFT JOIN bricks
USING (rgb _ hex_ value) ;
E. SELECT
EROM colors C
LEET JOIN bricks b
ON b. color_ rgb_ hex value = c. rgb. hex.

Answer: A,B

Explanation:
value
WHERE b. brick_ id > 0;

NEW QUESTION # 179
......

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