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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I |
| Exam Number: | JS-Dev-101 |
| Real Exam Qty: | 60 (plus up to 5 unscored pilot questions) |
| Certificate Validity Period: | Lifetime (No renewal required) |
| Exam Duration: | 105 minutes |
| Passing Score: | 65% |
| Related Certifications: | Lightning Web Components Specialist Superbadge Salesforce Certified JavaScript Developer I |
| Exam Format: | Multiple Select, Multiple Choice |
| Available Languages: | English |
| Exam Price: | $200 USD |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online (Proctored) |
| Pre Condition: | Completion of the Lightning Web Components Specialist Superbadge is required to earn the full credential, though it can be completed before or after the exam. |
| Official Syllabus URL: | https://trailhead.salesforce.com/en/credentials/javascriptdeveloperi |
>> JS-Dev-101 Fragen Beantworten <<
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116. Frage
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */;
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?
Antwort: A
Begründung:
We have a ternary:
account.style.display = accountName.includes(parsedSearchString)
? /* if true */
/* if false */;
Requirement:
If the account matches the search string → show it.
If it does not match → hide it.
For display:
Show: 'block' (or similar visible value).
Hide: 'none'.
So we want:
account.style.display = accountName.includes(parsedSearchString)
? 'block'
'none';
That corresponds to option A.
Why others are wrong:
B, C use values suitable for visibility, not display.
D ('none' : 'block') inverts the logic, hiding matches and showing non-matches.
117. Frage
Refer to the code below:
const pi = 3.1415926;
What is the data type of pi?
Antwort: A
Begründung:
In JavaScript, there is only one numeric type for ordinary numbers: number.
JavaScript number is a double-precision 64-bit binary format (IEEE 754).
There is no separate float, double, or decimal type in core JavaScript.
So:
typeof pi === 'number';
Hence, the correct answer is:
A . Number
Options B, C, D are specific numeric types found in other languages (like C, Java, C#), not distinct types in JavaScript.
Study Guide Concepts:
JavaScript primitive types
typeof operator and number
Lack of separate float / double / decimal types in JS
118. Frage
A developer has the function, shown below, that is called when a page loads.
function onload() {
console.log("Page has loaded!");
}
Where can the developer see the log statement after loading the page in the browser?
Antwort: B
119. Frage
Given the code below:
01 setTimeout(() => {
02 console.log(1);
03 }, 1100);
04 console.log(2);
05 new Promise((resolve, reject) => {
06 setTimeout(() => {
07 reject(console.log(3));
08 }, 1000);
09 }).catch(() => {
10 console.log(4);
11 });
12 console.log(5);
What is logged to the console?
Antwort: D
Begründung:
Comprehensive and Detailed Explanation From JavaScript Knowledge:
We must track synchronous code, setTimeout callbacks (macrotasks), and Promise rejection handling (microtasks).
Step-by-step:
Synchronous code first:
Line 01-03: Schedules a timeout at 1100 ms: logs 1 (later).
Line 04: console.log(2); → logs 2.
Lines 05-09: Construct a new Promise.
The executor runs immediately.
Inside it, another setTimeout is set for 1000 ms:
setTimeout(() => {
reject(console.log(3));
}, 1000);
Line 09-11: .catch(() => { console.log(4); }) attached to the promise.
Line 12: console.log(5); → logs 5.
So after all synchronous code, the console has:
2
5
At 1000 ms: inner setTimeout fires
The callback:
() => {
reject(console.log(3));
}
Inside:
console.log(3) runs first, logging 3.
console.log(3) returns undefined.
Then reject(undefined) is called.
So at about 1000 ms, we log:
3
When the promise is rejected:
The .catch handler is scheduled as a microtask.
After the current macrotask (the timeout callback) completes, the microtask queue runs.
Thus .catch(() => { console.log(4); }) runs shortly after, in the same 1000 ms tick.
So immediately after 3, the catch handler logs:
4
Now the logs in order are:
2
5
3
4
At 1100 ms: outer setTimeout fires
The callback from line 01 runs:
console.log(1);
Logs: 1.
Final log order:
2 (line 4, sync)
5 (line 12, sync)
3 (1000 ms timeout, then inside logs before reject)
4 (promise catch microtask after rejection)
1 (1100 ms timeout)
Concatenated: 25341.
Therefore, the correct option is:
Study Guide / Concept Reference (no links):
Event loop: call stack, macrotask queue (timers), microtask queue (promises) setTimeout scheduling and ordering Promise rejection, .catch, and microtasks Evaluation order of function arguments (reject(console.log(3)))
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120. Frage
Code:
01 const sayHello = (name) => {
02 console.log('Hello ', name);
03 };
04
05 const world = () => {
06 return 'World';
07 };
08
09 sayHello(world);
This does not print "Hello World".
What change is needed?
Antwort: A
Begründung:
Currently:
sayHello expects a value name and prints it.
world is a function that returns 'World'.
sayHello(world); passes the function object itself, not the result of calling it.
So name inside sayHello is a function, not the string "World".
To keep the call sayHello(world) yet get "World", sayHello must call the function parameter:
const sayHello = (name) => {
console.log('Hello', name());
};
Now:
sayHello(world) passes the function.
Inside sayHello, name() calls world(), which returns "World".
The console logs "Hello World".
Why the others are wrong:
B: Changing line 7 to }(); would attempt to IIFE the function definition and break the declaration.
C: sayHello(world)() would try to call the return value of sayHello, which is undefined, causing an error.
D: Changing world to a function declaration does not change the fact that it is passed as a function reference; sayHello still prints the function object, not 'World'.
121. Frage
......
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