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NEW QUESTION # 82
Refer to the HTML below:
Which JavaScript statement results in changing " The Lion."?
Answer: A
NEW QUESTION # 83
Which statement accurately describes the behavior of the async/await keywords?
Answer: D
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge When async is added to a function:
async function example() {}
JavaScript guarantees:
The function always returns a Promise, regardless of what is returned inside.
Inside the function, await pauses execution until a Promise resolves.
Code appears synchronous even though it uses asynchronous behavior.
Analysis of each option:
A incorrect:
Not "sometimes"-an async function always returns a Promise.
B incorrect:
Async functions can be called just like normal functions.
C incorrect:
Async/await has nothing to do with classes specifically.
D correct:
This is the standard description:
"Async functions behave asynchronously but allow writing code that looks synchronous."
________________________________________
JavaScript Knowledge Reference (text-only)
async functions always return Promises.
await pauses execution of the async function.
Async/await syntax creates synchronous-looking code on top of asynchronous operations.
NEW QUESTION # 84
Given the JavaScript below:
01 function filterDOM(searchString){
02 const parsedSearchString = searchString && searchString.toLowerCase();
03 document.querySelectorAll('.account').forEach(account => {
04 const accountName = account.innerHTML.toLowerCase();
05 account.style.display = accountName.includes(parsedSearchString) ? /* Insert code here */
06 });
07 }
Which code should replace the placeholder comment on line 05 to hide accounts that do not match the search string?
Answer: C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Line 05 uses the conditional (ternary) operator:
condition ? valueIfTrue : valueIfFalse
In this specific code:
account.style.display = accountName.includes(parsedSearchString)
? /* valueIfTrue */
: /* valueIfFalse */;
accountName.includes(parsedSearchString) returns:
true if the accountName string contains the parsedSearchString,
false otherwise.
The requirement is:
Hide accounts that do not match the search string.
That means:
If the account name includes the search string → it should be visible.
If the account name does not include the search string → it should be hidden.
The relevant property is:
account.style.display
For the display property:
Common values for showing elements:
'block', 'inline', 'inline-block', etc.
Common value for hiding elements:
'none' (element is not rendered and takes up no space).
So we want:
When accountName.includes(parsedSearchString) is true → show the element, e.g. display = 'block'.
When false → hide the element, display = 'none'.
Therefore the assignment should be:
account.style.display = accountName.includes(parsedSearchString) ? 'block' : 'none'; This matches option A:
'block' : 'none'
Why other options are incorrect:
B . 'none' : 'block'
This would hide matching accounts and show non-matching accounts, which is the opposite of the requirement.
C . 'hidden' : 'visible'
These are not valid values for the display property; they belong to the visibility property (visibility: 'hidden' | 'visible'), not display.
D . 'visible' : 'hidden'
Same issue as C: not valid for display, and reversed logic compared to requirement.
Thus, to correctly show matching accounts and hide non-matching ones, the ternary must be:
'block' : 'none'
Reference of JavaScript knowledge documents or Study Guide (concept names only):
Conditional (ternary) operator condition ? exprIfTrue : exprIfFalse
String.prototype.includes for substring checks
DOM APIs: document.querySelectorAll and forEach on NodeLists
Element styling via element.style.display
CSS display property: block vs none
________________________________________
NEW QUESTION # 85
Which statement accurately describes an aspect of promises?
Answer: C
NEW QUESTION # 86
Refer to the code below:
let inArray = [ [1, 2], [3, 4, 5] ];
Which two statements result in the array [1, 2, 3, 4, 5]?
(With corrected typing errors: usArray → inArray, .. → ....)
Answer: A,C
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
We start with the array:
let inArray = [ [1, 2], [3, 4, 5] ];
This is an array of two inner arrays:
First element: [1, 2]
Second element: [3, 4, 5]
The desired result is to transform this into a single, flat array:
[1, 2, 3, 4, 5]
This is accomplished by using Array.prototype.concat to concatenate the inner arrays into one new array, optionally combined with the spread syntax (...) or Function.prototype.apply.
Option A: [].concat(...inArray);
Relevant concepts:
Spread syntax (...inArray) expands an iterable into separate arguments.
Array.prototype.concat joins arrays or values into a new array. When you pass arrays as arguments to concat, it flattens them one level into the result.
Step-by-step behavior:
inArray is [ [1, 2], [3, 4, 5] ].
...inArray expands into [1, 2] and [3, 4, 5] as separate arguments.
So [].concat(...inArray) is equivalent to:
[].concat([1, 2], [3, 4, 5]);
concat processes each argument:
For [1, 2], it adds 1 and 2 into the result array.
For [3, 4, 5], it adds 3, 4, and 5 into the result array.
The final outcome is:
[1, 2, 3, 4, 5]
Therefore, Option A correctly produces the desired array.
Option B: [].concat.apply(inArray, []);
Corrected name from usArray to inArray.
Relevant concepts:
Function.prototype.apply(fnThis, argsArray) invokes a function with a specific this value and a list of arguments passed as an array.
Here:
thisArg is inArray.
argsArray is [] (no actual arguments passed).
So the call:
[].concat.apply(inArray, []);
is equivalent to:
Array.prototype.concat.apply(inArray, []);
// i.e. inArray.concat();
Since there are no extra arguments, inArray.concat() simply returns a shallow copy of inArray:
[ [1, 2], [3, 4, 5] ]
This remains an array of arrays and is not flattened into [1, 2, 3, 4, 5]. Therefore, Option B does not produce the required result.
Option C: [].concat::...inArray();
Corrected name from usArray to inArray and .. to ....
This expression uses syntax that is not part of standard JavaScript:
:: (double colon) was proposed in early drafts as a bind operator but is not part of the official ECMAScript standard.
The combination concat::...inArray() is invalid in normal JavaScript engines and cannot be used as a valid way to flatten arrays.
In addition, inArray() would imply calling inArray as a function, but it is an array, which would cause a runtime error.
Hence, Option C is syntactically or semantically invalid in standard JavaScript and does not provide the required result [1, 2, 3, 4, 5].
Option D: [].concat.apply({}, inArray);
Corrected name from usArray to inArray.
Relevant concepts:
Again, Function.prototype.apply is used to call concat with a specific this value and arguments provided as an array.
concat treats its this value as an array-like object but ultimately returns a new array containing concatenated elements.
In this expression:
[].concat.apply({}, inArray);
thisArg is {} (an empty object).
argsArray is inArray, which is [ [1, 2], [3, 4, 5] ].
Using apply, this is interpreted as calling concat like:
Array.prototype.concat.call({}, [1, 2], [3, 4, 5]);
concat then:
Starts from the array-like this (here {} is treated as an empty base).
Takes the first argument [1, 2] and appends its elements 1 and 2 to the result.
Takes the second argument [3, 4, 5] and appends its elements 3, 4, and 5 to the result.
The resulting new array is:
[1, 2, 3, 4, 5]
Therefore, Option D also correctly produces the required array.
Final evaluation of all options:
Option A: Uses spread syntax with concat and correctly flattens one level: [1, 2, 3, 4, 5].
Option B: Equivalent to inArray.concat(), leaving it as [[1, 2], [3, 4, 5]]. Does not flatten the structure.
Option C: Uses non-standard and invalid syntax; not a valid or correct JavaScript solution.
Option D: Uses apply with concat, passing the inner arrays as arguments and flattening one level to [1, 2, 3, 4, 5].
Thus, the two correct statements are:
Reference of JavaScript knowledge documents or Study Guide (concept names only):
Array.prototype.concat (concatenating and one-level flattening behavior) Spread syntax for arrays (...array) Function.prototype.apply (calling a function with a given this value and arguments list) Array flattening by one level using concat with array arguments Distinction between nested arrays and flat arrays in JavaScript
NEW QUESTION # 87
......
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