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Oracle 1z0-071 certification exam is designed for SQL developers, database administrators, and database analysts who want to validate their knowledge and skills in SQL. 1z0-071 exam covers the basics of SQL, including data manipulation, data definition, and data control language. It also includes advanced topics such as subqueries, set operators, and data aggregation.
Oracle 1z0-071 (Oracle Database SQL) Certification Exam is an industry-recognized certification that validates the skills of SQL developers, database administrators, and database designers. 1z0-071 Exam is designed to test the candidate's knowledge of SQL language, database concepts, and data modeling. The Oracle 1z0-071 certification is considered one of the most prestigious certifications in the IT industry, and it is highly recognized by leading IT organizations worldwide.
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Oracle 1z0-071 exam comprises of 73 multiple-choice questions that must be completed in 100 minutes. 1z0-071 exam is computer-based and is delivered at authorized testing centers worldwide. Candidates must score at least 63% to pass the exam, and the results are available immediately after the exam. 1z0-071 Exam Fee varies depending on the location, and candidates can register for the exam on the Oracle website.
Oracle Database SQL Sample Questions (Q109-Q114):
NEW QUESTION # 109
In the EMPLOYEES table there are 1000 rows and employees are working in the company for more than
10 years.
Evaluate the following SQL statement:

What would be the result?
- A. It gives an error because multiple NVL functions are used in an expression.
- B. It executes successfully and updates the records of those employees who have been working in the company for more than 600 days.
- C. It gives an error because NVL function cannot be used with UPDATE.
- D. It executes successfully but no rows updated.
Answer: B
NEW QUESTION # 110
View the Exhibit and examine the structure of the ORDERS table.

Which UPDATE statement is valid?
- A. UPDATE ordersSET order_date = '12-mar-2007',AND order_total
TO_NUMBER(NULL)WHERE order_id = 2455; - B. UPDATE ordersSET order_date = '12-mar-2007',order_total IS NULLWHERE order_id
= 2455; - C. UPDATE ordersSET order_date = '12-mar-2007',order_total = NULLWHERE order_id
2455; - D. UPDATE ordersSET order_date = TO_DATE('12-mar-2007','dd-mon-yyyy'),SET order_total = TO_NUMBER (NULL)WHERE order_id = 2455;
Answer: C
NEW QUESTION # 111
View the exhibit and examine the structure of the CUSTOMERS table.

Which two tasks would require subqueries or joins to be executed in a single statement? (Choose two.)
- A. listing of those customers, whose credit limit is the same as the credit limit of customers residing in the city 'Tokyo'.
- B. finding the number of customers, in each city, whose marital status is 'married'.
- C. listing of customers who do not have a credit limit and were born before 1980
- D. finding the average credit limit of male customers residing in 'Tokyo' or 'Sydney'
- E. finding the number of customers, in each city, whose credit limit is more than the average credit limit of all the customers
Answer: A,E
NEW QUESTION # 112
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTSand TIMEStables.

The PROD_IDcolumn is the foreign key in the SALEStable referencing the PRODUCTStable.
The CUST_IDand TIME_IDcolumns are also foreign keys in the SALEStable referencing the CUSTOMERS and TIMEStables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?
- A. The NEW_SALEStable would not get created because the column names in the CREATETABLE command and the SELECTclause do not match.
- B. The NEW_SALEStable would get created and all the FOREIGNKEYconstraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
- C. The NEW_SALEStable would get created and all the NOTNULLconstraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
- D. The NEW_SALEStable would not get created because the DEFAULTvalue cannot be specified in the column definition.
Answer: C
NEW QUESTION # 113
View the Exhibit and examine the structure of the PRODUCTS table. (Choose the best answer.) You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?
- A. It executes successfully and gives the correct output.
- B. It generates an error because = is not valid and should be replaced by the IN operator.
- C. It executes successfully but does not give the correct output.
- D. It generate an error because the subquery does not have a GROUP BY clause.
Answer: D
NEW QUESTION # 114
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