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NEW QUESTION # 132
Which statement allows a developer to update the browser navigation history without a page refresh?
Answer: D
NEW QUESTION # 133
Refer to the following code:
01 class Ship {
02 constructor(size) {
03 this.size = size;
04 }
05 }
06
07 class FishingBoat extends Ship {
08 constructor(size, capacity){
09 //Missing code
10 this.capacity = capacity;
11 }
12 displayCapacity() {
13 console.log('The boat has a capacity of ${this.capacity} people.');
14 }
15 }
16
17 let myBoat = new FishingBoat('medium', 10);
18 myBoat.displayCapacity();
Which statement should be added to line 09 for the code to display
The boat has a capacity of 10 people?
Answer: C
Explanation:
FishingBoat extends Ship, so it is a subclass. In ES6 classes:
When you define a constructor in a subclass, you must call super(...) before accessing this.
super(size) calls the parent class (Ship) constructor, which sets this.size = size.
So the correct constructor is:
class FishingBoat extends Ship {
constructor(size, capacity) {
super(size); // line 09
this.capacity = capacity;
}
displayCapacity() {
console.log(`The boat has a capacity of ${this.capacity} people.`);
}
}
Why others are incorrect:
B . ship.size = size;
ship is not defined; this would cause a ReferenceError.
C . super.size = size;
super is not an instance; you must call super(...) as a function to invoke the parent constructor.
D . this.size = size;
In a subclass constructor, you must call super() before using this, otherwise you get a ReferenceError. Also this bypasses the parent constructor logic.
Relevant concepts: ES6 class inheritance, extends, super() in subclass constructors, this initialization rules.
NEW QUESTION # 134
Refer to the code below:
01 new Promise((resolve, reject) => {
02 const fraction = Math.random();
03 if (fraction > 0.5) reject('fraction > 0.5, ' + fraction);
04 resolve(fraction);
05 })
06 .then(() => console.log('resolved'))
07 .catch((error) => console.error(error))
08 .finally(() => console.log('when am I called?'));
When does Promise.finally on line 08 get called?
Answer: A
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
Behavior of Promise.prototype.finally:
.finally(handler) registers a callback that runs when the promise is settled, meaning:
Either fulfilled (resolved), or
rejected.
Important points:
The finally callback does not receive the promise's value or error (unlike then and catch).
It is executed after the promise is settled, but before the resolution value or rejection reason is passed further down the chain.
It runs in both success and failure paths.
In the given code:
The promise may either:
Call reject('fraction > 0.5, ' + fraction) if fraction > 0.5, or
Call resolve(fraction) otherwise.
In both cases:
If it resolves, .then(() => console.log('resolved')) runs, and then .finally(...) is executed.
If it rejects, .catch((error) => console.error(error)) runs, and then .finally(...) is executed.
So .finally runs:
Not just "when rejected".
Not just "when resolved".
But whenever the promise is resolved or rejected.
Therefore, the correct choice is:
D . When resolved or rejected.
NEW QUESTION # 135
Refer to the code declarations below:
let st=1 = 'Java';
let st=2 = 'Script';
Which three expressions return the string `JavaScript`?
Choose 3 answers
Answer: A,C,D
NEW QUESTION # 136
Which option is true about the strict mode in imported modules?
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
In JavaScript, ES modules (files imported using import / export) have special semantics:
All code inside a module is automatically executed in strict mode.
This is specified by the ECMAScript standard and does not require the explicit "use strict"; directive.
Effects:
You do not need to write "use strict"; at the top of a module file.
You cannot turn strict mode off for module code.
All module top-level code is treated as strict.
Now evaluate each option:
Option A:
Add the statement use non-strict; before any other statements in the module to enable notstrict mode.
There is no use non-strict; directive in JavaScript.
The only directive recognized by engines is "use strict";.
You cannot explicitly enable a "non-strict" mode with such a string.
Option B:
Imported modules are in strict mode whether you declare them as such or not.
This matches the language specification.
ES modules are always in strict mode, automatically.
This is true.
Option C:
Add the statement use strict = false; before any other statements in the module to enable notstrict mode.
use strict = false; is not a directive; it is parsed as a normal expression, and does not affect strict mode.
There is no supported way to disable strict mode in modules.
Option D:
A developer can only reference notStrict() functions from the imported module.
There is no special notStrict() restriction in modules.
Functions exported/imported in modules are simply subject to strict mode rules like the rest of the module's code.
Therefore, the only correct statement is:
Study Guide / Concept Reference (no links):
ES modules (import / export)
Automatic strict mode in modules
"use strict"; directive for scripts vs modules
Inability to disable strict mode in ES module code
________________________________________
NEW QUESTION # 137
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