WGU Applied-Algebra最新試題,新版Applied-Algebra題庫

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WGU Applied-Algebra Exam Syllabus Topics:
| Section | Objectives |
|---|
| Topic 1: Functions and Graphs | - Function Concepts
- 1. Function notation
- 2. Domain and range
- Graphing Functions
- 1. Coordinate plane interpretation
- 2. Transformations of graphs
|
| Topic 2: Polynomial and Rational Expressions | - Polynomials
- 1. Factoring techniques
- 2. Operations with polynomials
- Rational Expressions
- 1. Restrictions on variables
- 2. Simplification
|
| Topic 3: Foundations of Algebra | - Algebraic Expressions
- 1. Simplifying expressions
- 2. Evaluating expressions
- 3. Order of operations
- Equations and Inequalities
- 1. Linear equations in one variable
- 2. Inequalities and interval notation
|
| Topic 4: Exponential and Logarithmic Concepts | - Logarithmic Basics
- 1. Conversion between exponential and logarithmic form
- 2. Logarithm properties
- Exponential Functions
- 1. Growth and decay models
- 2. Exponential equations
|
| Topic 5: Linear Functions and Systems | - Systems of Equations
- 1. Elimination method
- 2. Substitution method
- Linear Equations
- 1. Point-slope form
- 2. Slope-intercept form
|
>> WGU Applied-Algebra最新試題 <<
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最新的 Courses and Certificates Applied-Algebra 免費考試真題 (Q56-Q61):
問題 #56
The graph shows the daily practice duration for a musician, where the number of days since the beginning of the month is along the horizontal axis and the number of minutes practiced per day is along the vertical axis.

Based on the graph, what was the practice duration for day 8?
- A. 120 minutes
- B. 118 minutes
- C. 117 minutes
- D. 115 minutes
答案:D
解題說明:
This question asks us to interpret a value from a graph.
The horizontal axis represents:
Days
The vertical axis represents:
Practice duration in minutes
We need to find the practice duration on day 8.
To do this:
Locate 8 on the horizontal axis.
Move vertically until you reach the blue graph.
Read the corresponding value on the vertical axis.
From the graph, when:
x=8
the blue graph is at:
y=115
So the musician practiced for:
115 minutes
問題 #57
Which statement correctly interprets u(8), given that u(t)=0.21t
3
#4.09t
2
+18.89t+69.5 represents the number of units, u, in an inventory warehouse t hours after 9:00 a.m.?
- A. There are approximately 66 units in the inventory at 5:00 p.m.
- B. There are approximately 160 units in the inventory at 10:00 a.m.
- C. There are approximately 160 units in the inventory at 5:00 p.m.
- D. There are approximately 66 units in the inventory at 10:00 a.m.
答案:A
解題說明:
The function u(t) gives the number of units in the inventory warehouse t hours after 9:00 a.m. The expression u(8) means the value of the inventory function 8 hours after 9:00 a.m. Since 8 hours after 9:00 a.m. is 5:00 p.
m., the time must be 5:00 p.m., not 10:00 a.m. Now evaluate the function: u(8)=0.21(8)
3
#4.09(8)
2
+18.89(8)+69.5. This gives approximately 66.38, which rounds to about 66 units. Therefore, the correct interpretation is that there are approximately 66 units in the inventory at 5:00 p.m.
問題 #58
The graphed function n(t)represents the number of people, n, at a park thours after 8:00 a.m. The plotted points Aand Bhave coordinates (2#110)and (6#182).

Which statement gives the correct interpretation of the average rate of change of the number of people over the interval from point Ato point B?
- A. The number of people at the park increases at an average rate of 9 per hour.
- B. The number of people at the park decreases at an average rate of 9 per hour.
- C. The number of people at the park decreases at an average rate of 18 per hour.
- D. The number of people at the park increases at an average rate of 18 per hour.
答案:D
解題說明:
The average rate of change measures how much the output changes per one unit of input.
Here:
t= " hours after 8:00 a.m. "
and
n(t)= " number of people at the park "
The two given points are:
A=(2,110)
and
B=(6,182)
This means:
At t=2hours after 8:00 a.m., there were 110people at the park.
At t=6hours after 8:00 a.m., there were 182people at the park.
Now calculate the average rate of change:
" Average rate of change " =(182-110)/(6-2)
=72/4
=18
Because the value is positive, the number of people is increasing.
So the correct interpretation is:
" The number of people at the park increases at an average rate of 18 people per hour. "
問題 #59
A factory mixes two colors, red and yellow, to create a dye.

The graph shows the relationship between the amounts of each dye, where rrepresents the amount of red dye and yrepresents the amount of yellow dye.
What is the correct interpretation of the rate of change?
- A. The amount of yellow dye must be the amount of red dye plus 9/2.
- B. The amount of yellow dye must be the amount of red dye plus 2/9.
- C. The amount of yellow dye must be 9/2of the amount of red dye.
- D. The amount of yellow dye must be 2/9of the amount of red dye.
答案:C
解題說明:
The graph shows a linear relationship between the amount of red dye, r, and the amount of yellow dye, y.
The rate of change of a line is the slope:
" slope " =( " change in " y)/( " change in " r)
From the graph, the line goes through the origin and rises steeply. A clear point on the line is approximately:
(2#9)
This means when the amount of red dye is 2gallons, the amount of yellow dye is 9gallons.
So the rate of change is:
9/2
That means for every 2gallons of red dye, the factory uses 9gallons of yellow dye.
The relationship can be written as:
y=9/2 r
So the correct interpretation is:
" The amount of yellow dye must be " 9/2 " of the amount of red dye. "
Therefore, the correct answer is:
# ( " A " )
問題 #60
In the graph showing the number of new customer accounts, the horizontal axis shows the number of weeks since the beginning of winter and the vertical axis shows the number of new customer accounts. More customer accounts are opened during snowy weeks than during weeks without snow.

When was it likely snowy?
- A. It was likely snowy during weeks 7 and 14.
- B. It was likely snowy during weeks 1 and 5.
- C. It was likely snowy during only week 7.
- D. It was likely snowy during only week 1.
答案:A
解題說明:
This question asks us to interpret unusually high values on a graph. The problem states that more customer accounts are opened during snowy weeks than during weeks without snow. Therefore, the likely snowy weeks correspond to the peaks on the graph, where the number of new customer accounts is noticeably higher than surrounding weeks. The graph shows clear spikes at approximately week 7 and week 14. These weeks have higher account openings compared with nearby weeks, making them the best evidence of snowy conditions.
Week 1 and week 5 do not match the main peaks shown in the graph. Since the snowy weeks should correspond to the highest customer-account values, the correct answer is D.
問題 #61
......
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