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NEW QUESTION # 115
Given the code below:
01 setTimeout(() => {
02 console.log(1);
03 }, 1100);
04 console.log(2);
05 new Promise((resolve, reject) => {
06 setTimeout(() => {
07 reject(console.log(3));
08 }, 1000);
09 }).catch(() => {
10 console.log(4);
11 });
12 console.log(5);
What is logged to the console?
Answer: C
Explanation:
We must track synchronous code, setTimeout callbacks (macrotasks), and Promise rejection handling (microtasks).
Step-by-step:
Synchronous code first:
Line 01-03: Schedules a timeout at 1100 ms: logs 1 (later).
Line 04: console.log(2); β logs 2.
Lines 05-09: Construct a new Promise.
The executor runs immediately.
Inside it, another setTimeout is set for 1000 ms:
setTimeout(() => {
reject(console.log(3));
}, 1000);
Line 09-11: .catch(() => { console.log(4); }) attached to the promise.
Line 12: console.log(5); β logs 5.
So after all synchronous code, the console has:
2
5
At 1000 ms: inner setTimeout fires
The callback:
() => {
reject(console.log(3));
}
Inside:
console.log(3) runs first, logging 3.
console.log(3) returns undefined.
Then reject(undefined) is called.
So at about 1000 ms, we log:
3
When the promise is rejected:
The .catch handler is scheduled as a microtask.
After the current macrotask (the timeout callback) completes, the microtask queue runs.
Thus .catch(() => { console.log(4); }) runs shortly after, in the same 1000 ms tick.
So immediately after 3, the catch handler logs:
4
Now the logs in order are:
2
5
3
4
At 1100 ms: outer setTimeout fires
The callback from line 01 runs:
console.log(1);
Logs: 1.
Final log order:
2 (line 4, sync)
5 (line 12, sync)
3 (1000 ms timeout, then inside logs before reject)
4 (promise catch microtask after rejection)
1 (1100 ms timeout)
Concatenated: 25341.
Therefore, the correct option is:
Answe r: A
Study Guide / Concept Reference (no links):
Event loop: call stack, macrotask queue (timers), microtask queue (promises) setTimeout scheduling and ordering Promise rejection, .catch, and microtasks Evaluation order of function arguments (reject(console.log(3)))
NEW QUESTION # 116
A developer is trying to convince management that their team will benefit from using Node.js for a backend server that they are going to create. The server will be a web server that handles API requests from a website that the team has already built using HTML, CSS, and JavaScript.
Which three benefits of Node.js can the developer use to persuade their manager?
Choose 3 answers
Answer: B,D,E
NEW QUESTION # 117
Universal Containers (UC) just launched a new landing page, but users complain that the website is slow. A developer found some functions that might cause this problem. To verify this, the developer decides to execute everything and log the time each of these three suspicious functions consumes.
01 console.time('Performance');
02
03 maybeAHeavyFunction();
04
05 thisCouldTakeTooLong();
06
07 orMaybeThisOne();
08
09 console.endTime('Performance');
Which function can the developer use to obtain the time spent by every one of the three functions?
Answer: B
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
JavaScript consoles (browsers and Node) provide timing utilities:
console.time(label) - starts a timer with the given label.
console.timeEnd(label) - stops the timer and logs the total elapsed time.
console.timeLog(label) - logs the current elapsed time without stopping the timer.
To measure the time taken by each function separately while still using a single overall timer, you can log intermediate times:
console.time('Performance');
maybeAHeavyFunction();
console.timeLog('Performance', 'after maybeAHeavyFunction');
thisCouldTakeTooLong();
console.timeLog('Performance', 'after thisCouldTakeTooLong');
orMaybeThisOne();
console.timeLog('Performance', 'after orMaybeThisOne');
console.timeEnd('Performance');
Each console.timeLog('Performance') call prints the elapsed time since console.time('Performance') was started, so you can infer how long each function took.
Note: console.endTime in the original snippet is incorrect; the real method is console.timeEnd.
Why other options are incorrect:
B . console.trace()
Prints a stack trace, not timing information.
C . console.timeStamp()
Used with browser performance tools; it does not directly show elapsed times like timeLog or timeEnd.
D . console.getTime()
Not a standard console method.
Thus, the function that can be used to obtain timing between calls is:
Study Guide Concepts:
console.time, console.timeLog, console.timeEnd
Measuring performance and intermediate timings
Standard console debugging API methods
NEW QUESTION # 118
static delay = async delay => {
return new Promise(resolve => {
setTimeout(resolve, delay);
});
};
static asyncCall = async () => {
await delay(1000);
console.log(1);
};
console.log(2);
asyncCall();
console.log(3);
Assume delay and asyncCall are in scope as functions.
What is logged to the console?
Answer: D
Explanation:
The correct answer is D, because JavaScript executes synchronous code first, while the code after await runs later after the Promise resolves.
The execution order is:
console.log(2);
This runs first, so JavaScript logs:
2
Then this line runs:
asyncCall();
The asyncCall() function starts executing. Inside it, JavaScript reaches:
await delay(1000);
The delay(1000) function returns a Promise that resolves after 1000 milliseconds:
return new Promise(resolve => {
setTimeout(resolve, delay);
});
Because await pauses the rest of the asyncCall() function, this line does not run immediately:
console.log(1);
Instead, JavaScript continues executing the remaining synchronous code outside the async function:
console.log(3);
So JavaScript logs:
3
After approximately 1000 milliseconds, the Promise returned by delay(1000) resolves. Then the paused async function continues and runs:
console.log(1);
So JavaScript logs:
1
Final console output:
2
3
1
Important JavaScript concepts involved:
An async function always returns a Promise.
The await keyword pauses execution only inside the async function where it appears.
Code outside the async function continues running normally.
setTimeout() schedules its callback to run later, after the current synchronous code has finished.
Therefore, the verified answer is D. 2 3 1.
NEW QUESTION # 119
A developer has the function, shown below, that is called when a page loads.
Where can the developer see the log statement after loading the page in the browser?
Answer: C
NEW QUESTION # 120
......
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