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Salesforce JS-Dev-101 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
Topic 2
  • Testing: Covers evaluating unit test effectiveness against a block of code and modifying tests to improve their coverage and reliability.
Topic 3
  • Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
  • falsy evaluations.
Topic 4
  • Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.

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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q83-Q88):

NEW QUESTION # 83
Refer to the code below:
Let car1 = new Promise((_ , reject) =>
setTimeout(reject, 2000, "car 1 crashed in" =>
Let car2 =new Promise(resolve => setTimeout(resolve, 1500, "car 2 completed") Let car3 =new Promise(resolve =>setTimeout(resolve, 3000, "car 3 completed") Promise.race(( car1, car2, car3))
.then (value => (
Let result = '$(value) the race.';)}
.catch(arr => {
console.log("Race is cancelled.", err);
});
What is the value of result when Promise.race executes?

Answer: A


NEW QUESTION # 84
Refer to the code declarations below:
let str1 = 'Java';
let str2 = 'Script';
Which three expressions return the string JavaScript?

Answer: A,D,E

Explanation:
The correct answers are A, B, and D.
The two variables are:
let str1 = 'Java';
let str2 = 'Script';
The goal is to combine them into:
JavaScript
Option A is correct because template literals can insert variables directly into a string:
`${str1}${str2}`
This becomes:
`${'Java'}${'Script'}`
Result:
JavaScript
Option B is correct because strings have a concat() method:
str1.concat(str2);
This joins str2 onto the end of str1.
Result:
JavaScript
Option D is correct because the + operator performs string concatenation when both operands are strings:
str1 + str2;
This becomes:
'Java' + 'Script'
Result:
JavaScript
The incorrect options:
Option C is not valid JavaScript for joining strings. const is used for declaring constants, not concatenating values.
Option E is incorrect because join() is an array method, not a string method. This would only work with an array, for example:
['Java', 'Script'].join('');
But str1 is a string, so:
str1.join(str2)
is invalid.
Therefore, the verified answers are A, B, and D.


NEW QUESTION # 85
In the browser, the window object is often used to assign variables that require the broadest scope in an application Node.js application does not have access to the window object by default.
Which two methods areused to address this ?
Choose 2 answers

Answer: A


NEW QUESTION # 86
Refer to the following object.

How can a developer access the fullName property for dog?

Answer: C


NEW QUESTION # 87
Value of:
true + 3 + '100' + null

Answer: D

Explanation:
The correct answer is A.
JavaScript evaluates the expression from left to right:
true + 3 + '100' + null
Step 1:
true + 3
In numeric addition, true is converted to:
1
So:
true + 3
becomes:
1 + 3
Result:
4
Step 2:
4 + '100'
Because one operand is a string, JavaScript performs string concatenation instead of numeric addition.
So:
4 + '100'
becomes:
"4100"
Step 3:
"4100" + null
Again, because one operand is already a string, JavaScript converts null into the string:
"null"
So the final result is:
"4100null"
Execution summary:
true + 3 + '100' + null
// 1 + 3 + '100' + null
// 4 + '100' + null
// "4100" + null
// "4100null"
Therefore, the verified answer is A.


NEW QUESTION # 88
......

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