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>> Fortinet FCSS_NST_SE-7.6最新な問題集 <<
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質問 # 23
Refer to the exhibit, which shows the output of get router info bgp summary.
Which two statements are true? (Choose two.)
正解：A、C
解説：
The get router info bgp summary output lists BGP neighbor status:
Prefix Reception: The "State/PfxRcd" column shows the number of prefixes received from the neighbor- neighbor 100.64.1.254 has "1", confirming option A.
Received Message Count: Under "MsgRcvd", 18 packets have been received from neighbor 100.64.1.254.
This matches option C.
The second neighbor 100.64.2.254 is in "Active" state and has received/sent 0 packets, indicating that its TCP connection is NOT established, disproving option B.
There is no indication anywhere that the router is "still calculating" prefixes; "Active" just means no session is established, so option D is incorrect.
References:
FortiOS BGP Command Reference: BGP Neighbor States, PfxRcd, and Counters
質問 # 24
Refer to the exhibit.
The administrator did not override the FortiGuard FODN or IP address in the FortiGate configuration Which IP address did FortiGate get when resolving the servicem,fortiguard.net name?
正解：C
解説：
The study guide explicitly explains the FortiGuard flags shown by diagnose debug rating:
D = Default
"IP addresses of servers received from DNS resolution"
It then clarifies even more specifically:
"D = The IP address FortiGate got when resolving the service.fortiguard.net name (usually two or three servers have this flag, if the administrator didn't overwrite the FortiGuard FQDN or IP address in the FortiGate configuration)" In the exhibit, among the answer choices, the IP address marked with the D flag is 208.91.112.194. Therefore, that is the IP FortiGate got from resolving service.fortiguard.net.
Why the other options are wrong:
B . 209.22.147.36 is not the correct choice because in the exhibit it is not the DNS-resolution entry identified by the D flag C . 64.26.151.37 has no D flag D . 96.45.33.65 has no D flag So the verified answer is: A.
質問 # 25
Refer to the exhibits.
An OSPF peer is advertising route 172.16.52.0/24. The local FortiGate is configured with an inbound distribution list that allows the 172.16.0.0/16 network to be injected into its routing table. However, the 1'2.16.52.0/24 subnet cannot be seen in the FIB.
Which two stops can the administrator of the local FortiGate take to ensure that the advertised 172.16. 52.0/24 subnet will be injected into the routing table? (Choose two.)
正解：A、D
解説：
The issue is caused by the strict matching logic of the configured Prefix List.
Current State: The rule is edit 1 with set prefix 172.16.0.0 255.255.0.0 and both ge (greater than or equal) and le (less than or equal) are unset.
Behavior: When ge and le are unset, FortiOS requires an exact match of the subnet mask. The current rule only matches the exact network 172.16.0.0/16. It denies 172.16.52.0/24 because the mask (/24) does not match the rule's mask (/16).
To fix this and inject 172.16.52.0/24, you must modify the list to match the /24 mask:
A . Add another entry to the prefix list to specifically allow the 172.16.52.0/24 network:
Creating a new rule (e.g., edit 2) with set prefix 172.16.52.0 255.255.255.0 will provide an exact match for the incoming route, allowing it to pass the distribute-list.
B . Change the ge value to 17:
By configuring set ge 17 on the existing rule (conceptually 172.16.0.0/16 ge 17), you change the logic from "exact match" to "range match".
This configuration tells the router to match any prefix starting with 172.16.x.x that has a subnet mask length of 17 or greater.
Since the incoming route is a /24, and 24 is greater than 17, the route will match the prefix list and be accepted.
Why other options are incorrect:
C: The option text appears to read "Change the ... value to 16". If this refers to le 16, it would enforce the mask to be exactly /16 or less, which still excludes /24.
D: Changing the default behavior to implicit allow defeats the purpose of a filter (security control) and is not a standard configuration step for fixing a single missing route.
Reference:
FortiGate Security 7.6 Study Guide (Routing): "In prefix-lists, if ge and le are not used, the subnet mask must match exactly. To match subnets within a range, you must define the prefix length boundaries using ge or le."
質問 # 26
Refer to the exhibit.
A partial output from an IKE real-time debug is shown
The administrator does not have access to (he remote gateway
Based on the debug output, which two conclusions can you draw? (Choose two.)
正解：A、C
解説：
To determine the correct conclusions, we analyze the specific lines in the IKE real-time debug output provided in the exhibit:
* Analysis for Option A (The remote peer is the initiating peer):
* Evidence: The very first line of the debug output reads: ike 0:624000:98: responder: main mode get 1st message...
* Explanation: The keyword responder indicates that this local FortiGate is receiving the connection request. Consequently, the remote peer must be the initiator sending the request. The phrase "get 1st message" confirms the local unit is receiving the initial packet of the negotiation sequence.
* Conclusion: This statement is True.
* Analysis for Option B (This is a phase 1 negotiation):
* Evidence: The same line mentions main mode.
* Explanation: In IPsec VPNs, Main Mode and Aggressive Mode are exclusively used for Phase
1 (IKE SA) negotiations. Phase 2 (Child SA) negotiations use Quick Mode. The presence of
"main mode" definitively identifies this as a Phase 1 exchange.
* Conclusion: This statement is True.
* Analysis for Option C (There is a Diffie-Hellman group mismatch):
* Evidence:
* Incoming proposal (Remote): Lists type=OAKLEY_GROUP, val=MODP2048 (Group
14) in the first proposal proposal.
* My proposal (Local): Lists type=OAKLEY_GROUP, val=MODP2048 (Group 14).
* Explanation: Since both the remote peer and the local gateway support and are proposing MODP2048 (Group 14), there is no Diffie-Hellman group mismatch. The actual mismatch visible in the logs is between the Encryption/Hash algorithms (Remote proposes AES-256/SHA2-
256, while Local proposes AES-128/SHA), but the DH groups match.
* Conclusion: This statement is False.
* Analysis for Option D (This is a phase 2 negotiation):
* Explanation: As established in the analysis for Option B, "Main Mode" is a Phase 1 protocol. If this were Phase 2, the debug would show "Quick Mode".
* Conclusion: This statement is False.
Reference:
FortiGate Security 7.6 Study Guide (IPsec VPN): "Phase 1 modes: Main mode and Aggressive mode." FortiOS Debugging documentation: Explains that "responder" indicates the device receiving the IKE initialization.
質問 # 27
Refer to the exhibit, which shows the output of diagnose sys session stat.
Which statement about the output shown in the exhibit is correct?
正解：B
解説：
The correct answer is D.
The exhibit shows:
session_count=591
clash=162
memory_tension_drop=0
TCP sessions:
166 in NONE state
1 in ESTABLISHED state
3 in SYN_SENT state
2 in TIME_WAIT state
The study guide explains the TCP protocol states and states explicitly:
"When a session is closed by both the sender and receiver, FortiGate keeps that session in the session table for a few seconds, to allow for any out-of-order packets that might arrive after the FIN/ACK packet. This is the state value 5." In diagnose sys session stat, the exhibit shows 2 in TIME_WAIT state. Since TIME_WAIT = state value 5, those are the sessions being kept briefly for possible out-of-order packets. That makes D correct.
Why the other options are wrong:
A is wrong because session_count=591 is the total number of sessions, while the TCP sessions shown add up to only 172 (166 + 1 + 3 + 2). So not all sessions in the table are TCP sessions.
B is wrong because the study guide says the number of sessions deleted because of low free memory is shown by memory_tension_drop, and in the exhibit it is 0, not 162.
C is wrong because the study guide defines ephemeral/open TCP sessions as those not fully established, but the exhibit does not say all 166 in NONE state are specifically "waiting to complete the three-way handshake." The clearest directly supported statement from the displayed states is the 2 TIME_WAIT sessions retained for out-of-order packets.
So the verified answer is: D.
質問 # 28
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