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Oracle 1z0-071 Exam Syllabus Topics:

Section	Objectives
SQL Retrieval	- Joins and set operations 1. INNER, OUTER, CROSS joins 2. UNION, INTERSECT, MINUS - SELECT statements and filtering data 1. WHERE clause and conditions 2. ORDER BY and row limiting
Data Manipulation and Schema Objects	- DML operations 1. INSERT, UPDATE, DELETE, MERGE - DDL operations 1. CREATE, ALTER, DROP tables and constraints
SQL Functions	- Conversion and conditional functions 1. TO_CHAR, TO_NUMBER, CASE expressions - Single-row functions 1. Character, numeric, date functions
Relational Database Concepts	- Tables, rows, columns, and relational model basics - Data types and database objects overview
Subqueries and Advanced SQL	- Single-row and multi-row subqueries - Correlated subqueries and nested queries

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Oracle Database SQL 認定 1z0-071 試験問題 (Q279-Q284):

質問 # 279
Examine the structure of the EMPLOYEEStable.

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?
SELECT last_name, hire_date, salary

A. FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100) UNION ALL (SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE-180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000); SELECT last_name, hire_date, salary
B. FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id
100))
UNION
SELECT last_name, hire_date, salary
FROM employees
WHERE hire_date > SYSDATE-180;
C. FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id
'100')
UNION
SELECT last_name, hire_date, salary
FROM employees
WHERE hire_date > SYSDATE-180
INTERSECT
SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000;
(SELECT last_name, hire_date, salary
D. FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100) INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE-180; SELECT last_name, hire_date, salary

正解：C

質問 # 280
Which three; statements are true about built-in data types?

A. A varchar2 blank pads column values only if the data stored Is non-numeric and contains no Special characters.
B. A blob stores unstructured binary data within the database.
C. A varchar2 column definition does not require the length to be specified.
D. A char column definition does not require the length to be specified.
E. A BFILE stores unstructured binary data In operating system files.
F. The default length for a char column Is always one character.

正解：B、E、F

質問 # 281
Examine the command:

What does ON DELETE CASCADE imply?

A. When the BOOKStable is dropped, the BOOK_TRANSACTIONStable is dropped.
B. When a row in the BOOKStable is deleted, the rows in the BOOK_TRANSACTIONStable whose BOOK_ID matches that of the deleted row in the BOOKStable are also deleted.
C. When a value in the BOOKS.BOOK_IDcolumn is deleted, the corresponding value is updated in the BOOKS_TRANSACTIONS.BOOK_IDcolumn.
D. When the BOOKStable is dropped, all the rows in the BOOK_TRANSACTIONStable are deleted but the table structure is retained.

正解：B

解説：
Explanation/Reference:

質問 # 282
Which two statements are true regarding the GROUP BY clause in a SQL statement? (Choose two.)

A. If the SELECT clause has an aggregate function, then those individual columns without an aggregate function in the SELECT clause should be included in the GROUP BY clause.
B. You can use column alias in the GROUP BY clause.
C. Using the WHERE clause before the GROUP BY clause excludes the rows before creating groups.
D. Using the WHERE clause after the GROUP BY clause excludes the rows after creating groups.
E. The GROUP BY clause is mandatory if you are using an aggregate function in the SELECT clause.

正解：A、C

質問 # 283
Examine the description of the ORDER_ITEMS table:

Examine this incomplete query:
SELECT DISTINCT quantity * unit_price total_paid FROM order_items ORDER BY <clause>; Which two can replace <clause> so the query completes successfully?

A. product_id
B. quantity
C. quantity * unit_price
D. quantity, unit_price
E. total_paid

正解：C、D

解説：
In a SELECT statement with DISTINCT, the ORDER BY clause can only order by expressions that are part of the SELECT list.
A . quantity alone is not sufficient to replace <clause> as it is not included in the SELECT list after DISTINCT.
B . This option can successfully replace <clause> because both quantity and unit_price are used in the SELECT expression, and thus their individual values are valid for the ORDER BY clause.
C . total_paid is an alias for the expression quantity * unit_price, but it cannot be used in the ORDER BY clause because Oracle does not allow aliases of expressions in DISTINCT queries to be used in ORDER BY.
D . product_id is not included in the SELECT list after DISTINCT and thus cannot be used in ORDER BY.
E . The expression quantity * unit_price is exactly what is selected, so it can replace <clause> and the query will complete successfully.
Reference:
Oracle Database SQL Language Reference, 12c Release 1 (12.1): "ORDER BY Clause"

質問 # 284
......

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