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Oracle Architecture
Indexing and Partitioning
Data Management Concepts
XML Fundamentals

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Oracle 1z1-071: Oracle Database SQL exam is a critical certification for professionals to demonstrate their proficiency in SQL database management. Oracle Database SQL certification exam covers a wide range of topics and requires individuals to be adequately trained and prepared to pass. With this certification, individuals can enjoy an array of opportunities in database management, increased pay and benefits, and gain client trust.

Oracle 1z1-071 (Oracle Database SQL) certification exam is a professional certification exam that verifies an individual's knowledge and skills in SQL programming language and Oracle database management systems. Passing 1z0-071 Exam can help individuals enhance their career opportunities and advance their knowledge and skills in database management and application development.

Oracle Database SQL Sample Questions (Q44-Q49):

NEW QUESTION # 44
Examine the structure of the EMPLOYEES table.

You must display the details of employees who have manager with MANAGER_ID 100, who were hired in the past 6 months and who have salaries greater than 10000.
Which query would retrieve the required result?

A. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = 100) UNION ALL (SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000);
B. (SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100)) UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180;
C. SELECT last_name, hire_date, salary
FROM employees
WHERE salary > 10000
UNION ALL
SELECT last_name, hire_date, salary
FROM employees
WHERE manager_ID = (SELECT employee_id FROM employees WHERE employee_id = 100) INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE- 180;
D. SELECT last_name, hire_date, salary
FROM employees
WHERE manager_id = (SELECT employee_id FROM employees WHERE employee_id = '100') UNION SELECT last_name, hire_date, salary FROM employees WHERE hire_date > SYSDATE -180 INTERSECT SELECT last_name, hire_date, salary FROM employees WHERE salary > 10000;

Answer: D

NEW QUESTION # 45
In which three situations does a transaction complete? (Choose three.)

A. when a data definition language (DDL) statement is executed
B. when a DELETE statement is executed
C. when a ROLLBACK command is executed
D. when a PL/SQL anonymous block is executed
E. when a TRUNCATE statement is executed after the pending transaction

Answer: A,C,E

Explanation:
References:
https://docs.oracle.com/cd/B19306_01/server.102/b14220/transact.htm

NEW QUESTION # 46
View the Exhibit and examine the structure of the PRODUCT_INFORMATIONtable.

You want to see the product names and the date of expiration of warranty for all the products, if the product is purchased today. The products that have no warranty should be displayed at the top and the products with maximum warranty period should be displayed at the bottom.
Which SQL statement would you execute to fulfill this requirement?
SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"

A. FROM product_information
WHERE warranty_period > SYSDATE
B. FROM product_information
ORDER BY SYSDATE-warranty_period
SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"
C. FROM product_information
ORDER BY SYSDATE
SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"
D. FROM product_information
ORDER BY SYSDATE+warranty_period
SELECT product_name, SYSDATE+warranty_period AS "Warranty expire date"

Answer: D

NEW QUESTION # 47
Table EMPLOYEEScontains columns including EMPLOYEE_ID, JOB_ID and SALARY.
Only the EMPLOYEE_ID column is indexed.
Rows exist for employees 100 and 200.
Examine this statement:

Which two statements are true? (Choose two.)

A. Employee 200 will have JOB_ID set to the same value as the JOB_ID of employee 100
B. Employees 100 will have JOB_ID set to the same value as the JOB_ID of employee 200
C. Employees 100 and 200 will have the same JOB_ID as before the update command
D. Employee 200 will have SALARY set to the same value as the SALARY of employee 100
E. Employees 100 and 200 will have the same SALARY as before the update command
F. Employee 100 will have SALARY set to the same value as the SALARY of employee 200

Answer: B,F

NEW QUESTION # 48
Examine the description of the CUSTOMERS table:

Which two SELECT statements will return these results:
CUSTOMER_ NAME
--------------------
Mandy
Mary

A. SELECT customer_ name FROM customers WHERE customer_ name KIKE .*Ma*';
B. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma%' ;
C. SELECT customer_ name FROM customers WHERE UPPER (customer_ name ) LIKE 'MA*. ;
D. SELECT customer_ name FROM customers WHERE customer_ name='*Ma*';
E. SELECT customer_ name FROM customers WHERE customer name LIKE 'Ma*';
F. SELECT customer_ name FROM customers WHERE UPPER (customer name) LIKE 'MA&';
G. SELECT customer_ name FROM customers WHERE customer_ name LIKE ' % a % ' ;

Answer: B,C

Explanation:
The SQL LIKE operator is used in a WHERE clause to search for a specified pattern in a column. Here are the evaluations of the options:
* A: The pattern ' % a % ' will match any customer names that contain the letter 'a' anywhere in the name, not necessarily those starting with 'Ma'.
* B: This is correct as 'Ma%' will match any customer names that start with 'Ma'.
* C: In SQL, the wildcard character is '%' not '*', therefore, the pattern 'Ma' is incorrect.
* D: This is the correct syntax. 'UPPER (customer_ name ) LIKE 'MA%'' will match customer names starting with 'Ma' in a case-insensitive manner.
* E: Again, '*' is not a valid wildcard character in SQL.
* F: The character '&' is not a wildcard in SQL.
* G: The operator 'KIKE' is a typo, and '.Ma' is not valid SQL pattern syntax.

NEW QUESTION # 49
......

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