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| Certification Vendor: | Salesforce |
|---|---|
| Exam Name: | Salesforce Certified JavaScript Developer I - Multiple Choice Exam (JS-Dev-101) |
| Exam Number: | JS-Dev-101 |
| Exam Duration: | 105 minutes |
| Available Languages: | English |
| Related Certifications: | Salesforce Platform Developer I Salesforce Platform Developer II |
| Certificate Validity Period: | 1 year (maintenance required annually in Salesforce certification program) |
| Passing Score: | 65% |
| Exam Format: | Multiple Choice Questions, Multiple Select Questions |
| Exam Price: | $200 USD |
| Real Exam Qty: | 60 (multiple choice) |
| Recommended Training: | Salesforce Trailhead - JavaScript Developer I MDN Web Docs - JavaScript Guide |
| Exam Registration: | Salesforce Certification Registration Kryterion Webassessor (Exam Delivery) |
| Sample Questions: | Salesforce JS-Dev-101 Sample Questions |
| Exam Way: | Online proctored exam via Salesforce authorized testing platform (e.g., Webassessor) |
| Pre Condition: | No formal prerequisites, but familiarity with JavaScript and web development is recommended. |
| Official Syllabus URL: | https://trailhead.salesforce.com/credentials/javascriptdeveloper |
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| トピック | 出題範囲 |
|---|---|
| トピック 1 |
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| トピック 2 |
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| トピック 3 |
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質問 # 117
Value of:
true + 3 + '100' + null
正解：C
解説：
The correct answer is A.
JavaScript evaluates the expression from left to right:
true + 3 + '100' + null
Step 1:
true + 3
In numeric addition, true is converted to:
1
So:
true + 3
becomes:
1 + 3
Result:
4
Step 2:
4 + '100'
Because one operand is a string, JavaScript performs string concatenation instead of numeric addition.
So:
4 + '100'
becomes:
"4100"
Step 3:
"4100" + null
Again, because one operand is already a string, JavaScript converts null into the string:
"null"
So the final result is:
"4100null"
Execution summary:
true + 3 + '100' + null
// 1 + 3 + '100' + null
// 4 + '100' + null
// "4100" + null
// "4100null"
Therefore, the verified answer is A.
質問 # 118
Refer to the following object.
```javascript
02 const dog = {
02 firstName: 'Beau',
03 lastName: 'Boo',
04 get fullName() {
05 return this.firstName + ' ' + this.lastName;
06 }
07 };
How can a developer access the fullName property for dog?
正解：D
質問 # 119
Given the following code:
Counter = 0;
const logCounter = () => {
console.log(counter);
);
logCounter();
setTimeout(logCOunter, 1100);
setInterval(() => {
Counter++
logCounter();
}, 1000);
What is logged by the first four log statements?
正解：A
質問 # 120
Function to test:
01 const sum3 = (arr) => {
02 if (!arr.length) return 0;
03 if (arr.length === 1) return arr[0];
04 if (arr.length === 2) return arr[0] + arr[1];
05 return arr[0] + arr[1] + arr[2];
06 };
Which two assert statements are valid tests for this function?
正解：A、C
解説：
Evaluate each test:
A . sum3([1, '2'])
Array length is 2 → line 4: arr[0] + arr[1] → 1 + '2' → '12' (string).
Assertion: '12' == 12 is true (type coercion).
However, this "test" is not logically correct: a numeric sum function should not be expected to return '12' as a string. It passes only because of weak equality coercion, so it is not a good/valid test of correct behavior.
B . sum3(['hello', 2, 3, 4])
Length ≥ 3 → line 5: 'hello' + 2 + 3 → 'hello2' + 3 → 'hello23'.
'hello23' === NaN is always false because NaN is never equal to anything, not even itself.
This assertion fails and also misunderstands how NaN comparisons work.
C . sum3([-3, 2])
Length 2 → -3 + 2 = -1.
Assertion: -1 === -1 → true.
This is a correct and meaningful test.
D . sum3([0])
Length 1 → returns arr[0] → 0.
Assertion: 0 === 0 → true.
Also a correct and meaningful test.
Therefore, the valid and logically correct tests here are C and D.
質問 # 121
myArraym can have one level, two levels, or more levels.
Which statement flattens myArray when it can be arbitrarily nested?
正解：C
質問 # 122
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