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| Section | Objectives |
|---|
| Topic 1: SQL Functions | - Single-row functions
- 1. Character, numeric, date functions
- Conversion and conditional functions
- 1. TO_CHAR, TO_NUMBER, CASE expressions
|
| Topic 2: Data Manipulation and Schema Objects | - DML operations
- 1. INSERT, UPDATE, DELETE, MERGE
- DDL operations
- 1. CREATE, ALTER, DROP tables and constraints
|
| Topic 3: Relational Database Concepts | - Data types and database objects overview - Tables, rows, columns, and relational model basics
|
| Topic 4: Subqueries and Advanced SQL | - Single-row and multi-row subqueries - Correlated subqueries and nested queries
|
| Topic 5: SQL Retrieval | - SELECT statements and filtering data
- 1. ORDER BY and row limiting
- 2. WHERE clause and conditions
- Joins and set operations
- 1. INNER, OUTER, CROSS joins
- 2. UNION, INTERSECT, MINUS
|
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Oracle Database SQL Sample Questions (Q26-Q31):
NEW QUESTION # 26
Examine the data in the CUST_NAME column of the CUSTOMERS table.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output?
- A. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,-2)<>0;
- B. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',-1,2)<>0;
- C. SELECT LPAD(SUBSTR(cust_name, INSTR (cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
- D. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
Answer: B,D
NEW QUESTION # 27
View the Exhibit and examine the structure of ORDER_ITEMS and ORDERS tables.

You need to remove from the ORDER_ITEMS table those rows that have an order status of 0 or 1 in the ORDERS table.
Which two DELETE statements are valid (Choose two.)
- A. DELETEFROM order_itemsWHERE order_id IN (SELECT order_idFROM ordersWHERE orders_status in (0,1));
- B. DELETE *FROM order_itemsWHERE order_id IN (SELECT order_id)FROM ordersWHERE order_status IN (0,1));
- C. DELETEFROM (SELECT * FROM order_items I,orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));
- D. DELETE FROM order_items iWHERE order_id = (SELECT order_id FROM orders oWHERE i.order_id = o.order_id AND order_status IN (0,1));
Answer: A,C
NEW QUESTION # 28
Examine the description of the EMPLOYEES table:

Examine this query:

Which line produces an error?
- A. Line 8
- B. Line 3
- C. Line 5
- D. Line 7
Answer: B
Explanation:
In the provided SQL query, the issue arises from the alias 'a.avg_sal' which is defined in the subquery but is being referenced in the SELECT list of the outer query. This is not permitted in SQL as the scope of the alias defined in the subquery is only within that subquery.
Here is the breakdown of the code and the error:
* Line 1: Correct syntax for initiating a SELECT statement.
* Line 2: Refers to 'e.salary', which is a correct reference to the 'salary' column using alias 'e' for the employees table.
* Line 3: 'a.avg_sal' attempts to reference an alias that is defined in the subquery within the outer query, which is not allowed. This is because 'avg_sal' is defined in the subquery's SELECT list and cannot be referenced outside of it. The correct way to include the average salary from the subquery in the SELECT list of the main query would be to repeat the subquery or to use a join that includes the average salary.
* Line 5-7: The subquery itself is correctly formed; it computes the average salary for the same department.
* Line 8: The ORDER BY clause is properly referencing 'e.last_name', which is defined in the outer query.
Therefore, the error occurs at Line 3 where 'a.avg_sal' is not a valid reference in the SELECT list of the main query because it is defined in the subquery.
The rules of scope for aliases in subqueries are specified in the Oracle Database SQL Language Reference 12c documentation. Subquery aliases cannot be referenced outside their subquery.
NEW QUESTION # 29
Which two statements are true regarding savepoints? (Choose two.)
- A. Savepoints can be used for both DML and DDL statements.
- B. Savepoints may be used to ROLLBACK.
- C. Savepoints can be used for only DML statements.
- D. Savepoints are effective only for COMMIT.
- E. Savepoints are effective for both COMMITand ROLLBACK.
Answer: B,C
Explanation:
Explanation/Reference: https://docs.oracle.com/cd/B19306_01/server.102/b14200/statements_10001.htm#SQLRF01701
NEW QUESTION # 30
Examine the data in the CUST_NAME column of the CUSTOMERS table.
CUST_NAME
-------------------
Renske Ladwig
Jason Mallin
Samuel McCain
Allan MCEwen
Irene Mikkilineni
Julia Nayer
You need to display customers' second names where the second name starts with "Mc" or "MC".
Which query gives the required output?
- A. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
SUBSTR(cust_name, INSTR(cust_name,' ')+1) LIKE INITCAP('MC%'); - B. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1))='Mc'; - C. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1)) = INITCAP('MC%'); - D. SELECT SUBSTR(cust_name, INSTR(cust_name,' ')+1)FROM customersWHERE
INITCAP(SUBSTR(cust_name, INSTR(cust_name,' ')+1)) LIKE 'Mc%';
Answer: D
NEW QUESTION # 31
......
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