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Salesforce Certified JavaScript Developer (JS-Dev-101) Sample Questions (Q21-Q26):
NEW QUESTION # 21
Refer to the code below:
01 function myFunction(reassign) {
02 let x = 1;
03 var y = 1;
04
05 if (reassign) {
06 let x = 2;
07 var y = 2;
08 console.log(x);
09 console.log(y);
10 }
11
12 console.log(x);
13 console.log(y);
14 }
What is displayed when myFunction(true) is called?
- A. 2 2 1 2
- B. 2 2 undefined undefined
- C. 2 2 1 1
- D. 2 2 2 2
Answer: A
Explanation:
This question tests understanding of let (block scope) and var (function scope) in JavaScript.
* Initial declarations in the function:
let x = 1; // line 2
var y = 1; // line 3
Here:
* x is declared with let, so it is block-scoped to the function body.
* y is declared with var, so it is function-scoped to the entire function.
* Inside the if (reassign) block (and since reassign is true, we enter it):
if (reassign) {
let x = 2; // line 6
var y = 2; // line 7
console.log(x); // line 8
console.log(y); // line 9
}
Detailed behavior:
* let x = 2; on line 6 creates a new block-scoped variable x that exists only inside the if block. It does not change the outer x declared on line 2.
* var y = 2; on line 7 declares y with var again, but var is function-scoped. This effectively reassigns the same y defined on line 3 for the entire function. After this line, y is 2 everywhere in the function.
Now, inside the if block:
* console.log(x); (line 8) logs the inner block-scoped x, which is 2.
* console.log(y); (line 9) logs y, which is the function-scoped y that was set to 2.
So the first two outputs are:
* 2
* 2
* After the if block, execution continues:
console.log(x); // line 12
console.log(y); // line 13
Outside the if block:
* The block-scoped let x = 2; no longer exists; it was only visible inside the if block.
* The outer let x = 1; (line 2) is still in scope and has not been changed.
Thus:
* console.log(x); (line 12) logs the outer x, which is still 1.
* console.log(y); (line 13) logs y which, due to var y = 2; inside the if, is now 2 for the whole function.
Therefore, when myFunction(true) is called, the output in order is:
* 2 (inner x in if)
* 2 (function-scoped y after reassignment)
* 1 (outer x after if)
* 2 (function-scoped y remains 2)
This corresponds to:
The answer: B (2 2 1 2)
JavaScript knowledge / study guide reference concepts:
* let declarations and block scope
* var declarations and function scope
* Shadowing of variables with let inside a block
* Re-declaration and reassignment of var within a function
* Execution order of statements and console output
NEW QUESTION # 22
Given the code below:
01 const delay = async delay = > {
02 return new Promise((resolve, reject) = > {
03 console.log(1);
04 setTimeout(resolve, delay);
05 });
06 };
07
08 const callDelay = async () = > {
09 console.log(2);
10 const yup = await delay(1000);
11 console.log(3);
12 };
13
14 console.log(4);
15 callDelay();
16 console.log(5);
What is logged to the console?
- A. 4 2 1 5 3
- B. 4 5 1 2 3
- C. 1 4 2 3 5
- D. 4 2 1 5 3
Answer: A
Explanation:
Execution order:
* Top-level code runs synchronously:
* Line 14: console.log(4); # logs 4.
* Line 15: callDelay(); is called.
* Inside callDelay:
* Line 9: console.log(2); # logs 2.
* Line 10: await delay(1000);:
* Calls delay(1000).
* Inside delay(1000):
* Line 3: console.log(1); # logs 1.
* Line 4: setTimeout(resolve, delay); schedules resolve in 1000 ms.
* delay returns a pending Promise. await pauses callDelay here and returns control to the event loop.
* Back to top-level:
* Line 16: console.log(5); # logs 5.
So synchronous log sequence is: 4, 2, 1, 5.
* After ~1000 ms:
* The setTimeout in delay resolves the Promise.
* The await in callDelay resumes.
* Line 11: console.log(3); # logs 3.
Final log order: 4 2 1 5 3.
Both A and B show the same sequence; one must be chosen, so A is correct.
Concepts: async/await flow, Promise resolution timing, event loop, and ordering of synchronous vs timer callbacks.
NEW QUESTION # 23
A developer has two ways to write a function:
Option A:
function Monster() {
This.growl = () => {
Console.log ("Grr!");
}
}
Option B:
function Monster() {};
Monster.prototype.growl =() => {
console.log("Grr!");
}
After deciding on an option, the developer creates 1000 monster objects.
How many growl methods are created with Option A Option B?
- A. 1 growl method is created for Option A. 1000 growl methods are created for Option B.
- B. 1000 growl method is created for Option A. 1 growl methods are created for Option B.
- C. 1000 growl methods are created regardless of which option is used.
- D. 1 growl method is created regardless of which option is used.
Answer: B
NEW QUESTION # 24
A developer wants to use a module called DataPrettyPrint. This module exports one default function called printDate ().
How can a developer import and use the printDate() function?
A)

B)

C)

D)

- A. Option D
- B. Option A
- C. Option B
- D. Option C
Answer: C
NEW QUESTION # 25
Refer to the code below:
new Promise((resolve, reject) => {
const fraction = Math.random();
if( fraction >0.5) reject("fraction > 0.5, " + fraction);
resolve(fraction);
})
.then(() =>console.log("resolved"))
.catch((error) => console.error(error))
.finally(() => console.log(" when am I called?"));

When does Promise.finally on line 08 get called?
- A. When resolved or rejected
- B. When rejected
- C. WHen resolved
- D. When resolved and settled
Answer: A
NEW QUESTION # 26
......
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