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| Topic | Details |
|---|
| Topic 1 | - Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
|
| Topic 2 | - Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
|
| Topic 3 | - Variables, Types, and Collections: Covers declaring and initializing variables, working with strings, numbers, dates, arrays, and JSON, along with understanding type coercion and truthy
- falsy evaluations.
|
>> JS-Dev-101 Associate Level Exam <<
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q142-Q147):
NEW QUESTION # 142
A developer wrote the following code:
01 let x = object.value;
02
03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 }
The developer has a getNextValue function to execute after handleObjectValue(), but does not want to execute getNextValue() if an error occurs. How can the developer change the code to ensure this behavior?
- A. 03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 } finally {
08 getNextValue();
09 } - B. 03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 }
08 getNextValue(); - C. 03 try {
04 handleObjectValue(x);
05 } catch(error) {
06 handleError(error);
07 } then {
08 getNextValue();
09 } - D. 03 try {
04 handleObjectValue(x);
05 getNextValue();
06 } catch(error) {
07 handleError(error);
08 }
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Requirement:
getNextValue() should run only if handleObjectValue(x) does not throw an error.
If an error occurs, handleError(error) should run, and getNextValue() should be skipped.
Option B:
try {
handleObjectValue(x);
getNextValue();
} catch (error) {
handleError(error);
}
Behavior:
If handleObjectValue(x) succeeds (no error):
Execution continues to getNextValue();.
If handleObjectValue(x) throws:
Control jumps directly to catch, getNextValue() is skipped.
handleError(error); is called.
This matches the requirement perfectly.
Why others are incorrect:
A: } then { is invalid JavaScript syntax.
C:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
}
getNextValue();
getNextValue() is called after the try...catch regardless of whether an error occurred. Not acceptable.
D: finally always runs:
try {
handleObjectValue(x);
} catch (error) {
handleError(error);
} finally {
getNextValue();
}
getNextValue() will execute in both success and error cases.
Therefore, the correct approach is B.
Concepts: try/catch control flow, finally semantics, placing code inside vs outside try/catch blocks.
________________________________________
NEW QUESTION # 143
A developer has a formatName function that takes two arguments, firstName and lastName and returns a string. They want to schedule the function to run once after five seconds.
What is the correct syntax toschedule this function?
- A. setTimout(() => { formatName("John', 'Doe') }, 5000);
- B. setTimeout (formatName(), 5000, "John", "BDoe");
- C. setTimeout (formatName('John', ''Doe'), 5000);
- D. setTimeout ('formatName', 5000, 'John", "Doe');
Answer: D
NEW QUESTION # 144
developer publishes a new version of a package with new features that do not break backward compatibility. The previous version number was 1.1.3.
Following semantic versioning format, what should the new package version number be?
- A. 1.1.4
- B. 1.2.0
- C. 2.0.0
- D. 1.2.3
Answer: C
NEW QUESTION # 145
Given the code below:
01 const delay = async delay => {
02 return new Promise((resolve, reject) => {
03 console.log(1);
04 setTimeout(resolve, delay);
05 });
06 };
07
08 const callDelay = async () => {
09 console.log(2);
10 const yup = await delay(1000);
11 console.log(3);
12 };
13
14 console.log(4);
15 callDelay();
16 console.log(5);
What is logged to the console?
- A. 4 2 1 5 3
- B. 4 5 1 2 3
- C. 1 4 2 3 5
- D. 4 2 1 5 3
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Execution order:
Top-level code runs synchronously:
Line 14: console.log(4); → logs 4.
Line 15: callDelay(); is called.
Inside callDelay:
Line 9: console.log(2); → logs 2.
Line 10: await delay(1000);:
Calls delay(1000).
Inside delay(1000):
Line 3: console.log(1); → logs 1.
Line 4: setTimeout(resolve, delay); schedules resolve in 1000 ms.
delay returns a pending Promise. await pauses callDelay here and returns control to the event loop.
Back to top-level:
Line 16: console.log(5); → logs 5.
So synchronous log sequence is: 4, 2, 1, 5.
After ~1000 ms:
The setTimeout in delay resolves the Promise.
The await in callDelay resumes.
Line 11: console.log(3); → logs 3.
Final log order: 4 2 1 5 3.
Both A and B show the same sequence; one must be chosen, so A is correct.
Concepts: async/await flow, Promise resolution timing, event loop, and ordering of synchronous vs timer callbacks.
________________________________________
NEW QUESTION # 146
Refer to the code below:
01 const exec = (item, delay) =>{
02 newPromise(resolve => setTimeout( () => resolve(item), delay)),
03 async function runParallel() {
04 Const (result1, result2, result3) = await Promise.all{
05 [exec ('x', '100') , exec('y', 500), exec('z', '100')]
06 );
07 return `parallel is done: $(result1)$(result2)$(result3)`;
08 }
}
}
Which two statements correctly execute the runParallel () function?
Choose 2 answers
- A. runParallel ( ). done(function(data){return data;});
- B. runParallel () .then(function(data)return data
- C. runParallel () .then(data);
- D. Async runParallel () .then(data);
Answer: A,B
NEW QUESTION # 147
......
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