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| Section | Objectives |
|---|---|
| Topic 1: Design and implement data distribution | - Partitioning and scaling
|
| Topic 2: Optimize and maintain Cosmos DB solutions | - Performance optimization
|
| Topic 3: Integrate Azure Cosmos DB with Azure services | - Data pipelines and analytics
|
| Topic 4: Design and implement data models for Azure Cosmos DB | - Model data for NoSQL workloads
|
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NEW QUESTION # 106
You are designing an Azure Cosmos DB for NoSQL solution to store data from IoT devices.
Writes from the devices will occur every second. Data will be retained indefinitely.
The following is a sample of the data.
You need to select a partition key that meets the following requirements for writes:
- Minimizes the partition skew
- Avoids capacity limits
- Avoids hot partitions
What should you do?
Answer: B
Explanation:
Correct:
* Create a new synthetic key that contains deviceId and a random number.
Use a partition key with a random suffix. Distribute the workload more evenly is to append a random number at the end of the partition key value. When you distribute items in this way, you can perform parallel write operations across partitions.
* Create a new synthetic key that contains deviceId and timestamp.
Concatenate multiple properties of an item.
You can form a partition key by concatenating multiple property values into a single artificial partitionKey property. These keys are referred to as synthetic keys.
For example, consider the following example document:
{
"deviceId": "abc-123",
"date": 2018
}
For the previous document, one option is to set /deviceId or /date as the partition key. Use this option, if you want to partition your container based on either device ID or date. Another option is to concatenate these two values into a synthetic partitionKey property that's used as the partition key.
{
"deviceId": "abc-123",
"date": 2018,
"partitionKey": "abc-123-2018"
Incorrect:
* Create a new synthetic key that contains deviceId and deviceManufacturer.
All the devices could have the same manufacturer.
* Create a new synthetic key that contains deviceId and sensor1Value.
Senser1Value has only two values.
* Use deviceId as the partition key.
* Use deviceManufacturer as the partition key.
All the devices could have the same manufacturer.
* Use sensor1Value as the partition key
* Use timestamp as the partition key.
You will also not like to partition the data on "DateTime", because this will create a hot partition.
Imagine you have partitioned the data on time, then for a given minute, all the calls will hit one partition. If you need to retrieve the data for a customer, then it will be a fan-out query because data may be distributed on all the partitions.
Reference:
https://docs.microsoft.com/en-us/azure/cosmos-db/sql/synthetic-partition-keys
https://docs.microsoft.com/en-us/azure/cosmos-db/concepts-limits
NEW QUESTION # 107
You have an Azure subscription that contains an Azure Cosmos DB for NoSQL database named DB1. The shared throughput provisioned for DB1 is 10,000 DTU/s. DB1 contains the containers shown in the following table.
You need to modify the throughput for the containers. The solution must meet the following requirements:
* The maximum throughput for Container1 must be 4,000 DTU/s.
* The throughput for Contained must be shared across the containers.
* Administrative effort must be minimized.
What should you do? To answer, select the appropriate options in the answer are a. NOTE: Each correct selection is worth one point.
Answer:
Explanation:
NEW QUESTION # 108
You have an Azure subscription that contains an Azure Cosmos DB for NoSQL account named account1.
Backups for account1 have the following configurations:
* Interval: 2 hours
* Retention period: 4 days
You need to estimate the charges associated with the retention of the backups. How many copies of the backups will incur additional charges?
Answer: D
NEW QUESTION # 109
Hotspot Question
You have an Azure Cosmos DB for NoSQL container. The container contains items that have the following properties.
You need to protect the data stored in the container by using Always Encrypted. For each property, you must use the strongest type of encryption and ensure that queries execute properly.
What is the strongest type of encryption that you can apply to each property? To answer, select the appropriate options in the answer area.
Answer:
Explanation:
NEW QUESTION # 110
You have a container that stores data about families. The following is a sample document.
For each of the following statements, select Yes if the statement is true. otherwise, select No.
NOTE: Each correct selection is worth one point.
Answer:
Explanation:
Explanation
Children who do no have parents defined will appear on the list = NO
Children who do not have parents defined will not appear on the list. This is because the document schema defines the children property as an array of objects that contain the firstName and gender properties of each child, as well as a parents property that references the id values of the parents. If a child does not have parents defined, it means that the parents property is either missing or empty for that child. Therefore, such a child will not be included in the list of children who have parents defined.
Children who have more than one pet will appear on the list multiple times. = Yes Children who have more than one pet will appear on the list multiple times. This is because the document schema defines the pets property as an array of objects that contain the givenName and type properties of each pet, as well as a children property that references the id values of the children who own the pet. If a child has more than one pet, it means that the child's id value will appear in the children property of multiple pet objects. Therefore, such a child will be included in the list of children who have pets multiple times.
Children who do no have pets defined will appear on the list = No
Children who do not have pets defined will not appear on the list. This is because the document schema defines the pets property as an array of objects that contain the givenName and type properties of each pet, as well as a children property that references the id values of the children who own the pet. If a child does not have pets defined, it means that the child's id value does not appear in the children property of any pet object.
Therefore, such a child will not be included in the list of children who have pets defined.
NEW QUESTION # 111
......
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