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Lpi 010-160 Exam Syllabus Topics:

Section	Objectives
Topic 1: The Power of the Linux Command Line	- Introduction to Shell and Scripting Concepts - Working with Text Streams - Basic Commands and Utilities
Topic 2: Security and File Permissions	- Basic Security Concepts - Users and Groups - File Permissions and Ownership
Topic 3: The Linux Community and a Career in Open Source	- Open Source Software and Licensing - ICT Skills and Working in Linux - Major Open Source Applications - Linux Evolution and Popular Operating Systems
Topic 4: The Linux Operating System	- Operating System Components - Package Management Basics - Processes and System Resources
Topic 5: Finding Your Way on a Linux System	- Command Line Basics - Filesystem Navigation - File and Directory Operations

>> 010-160考試備考經驗 <<

010-160考試備考經驗：Linux Essentials Certificate Exam - version 1.6考試即時下載|更新的Lpi 010-160

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最新的 LPI Linux Essentials 010-160 免費考試真題 (Q29-Q34):

問題 #29
Which of the following outputs could stem from the commandlast?

A. EXT4-fs (dm-7): mounted filesystem with ordered data mode. Opts: (null)
B. Password for user last changed at Sat Mar 31 16:38:57 EST 2018
C. 1 ls
2 cat text.txt
3 logout
D. Last login: Fri Mar 23 10:56:39 2018 from server.example.com
E. root tty2 Wed May 17 21:11 - 21:11 (00:00)

答案：E

解題說明：
Explanation
The last command in Linux is used to display the list of all the users logged in and out since the file /var/log/wtmp was created1. The output of the last command shows the username, the terminal, the IP address, the login time and date, and the duration of the session for each record2. The option E is the only one that matches this format. Theother options are not related to the last command. Option A shows a list of commands executed by a user. Option B shows the password change information for a user. Option C shows the last login information for a user. Option D shows the mount information for a filesystem. References:
* Linux Essentials Version 1.6 Objectives3, Topic 1.4: Command Line Basics, Subtopic: Basic Shell Commands
* Linux last Command Tutorial for Beginners (8 Examples)4
* Linux Essentials Version 1.6 Exam Preparation Guide, Section 1.4: Command Line Basics, Page 16

問題 #30
Which of the following examples shows the general structure of a for loop in a shell script?

A. for *.txt ( echo $i )
B. for ls *.txt exec {} \;
C. for *.txt as file => echo $file
D. foreach @{file} { echo $i
}
E. for file in *.txt do
echo $i done

答案：E

解題說明：
Explanation
The general structure of a for loop in a shell script is as follows12:
for variable in list do commands done
The variable is the name of a loop counter or iterator that takes on the values of the items in the list. The list can be a sequence of words, numbers, filenames, or the output of a command. The commands are the body of the loop that are executed for each value of the variable. The do and done keywords mark the beginning and the end of the loop body.
The option C. for file in *.txt do echo $i done follows this structure, with the variable being file, the list being
*.txt (which matches all the files with the .txt extension in the current directory), and the command being echo
$i (which prints the value of the variable i, which is presumably set somewhere else in the script).
The other options are incorrect because:
* A. for *.txt as file => echo $file uses an invalid syntax for a for loop. The as keyword is not part of the shell script syntax, and the => symbol is not a valid operator. The correct way to write this loop would be:
for file in *.txt do echo $file done
* B. for *.txt ( echo $i ) uses an invalid syntax for a for loop. The parentheses are not part of the shell script syntax, and the loop body is missing the do and done keywords. The correct way to write this loop would be:
for i in *.txt do echo $i done
* D. for ls *.txt exec {} ; uses an invalid syntax for a for loop. The ls command is not a valid variable name, and the exec {} ; is not a valid command. This looks like a mix of a for loop and a find command.
The correct way to write this loop would be:
for file in *.txt do exec $file done
* E. foreach @{file} { echo $i } uses an invalid syntax for a for loop. The foreach keyword is not part of the shell script syntax, and the @{file} and { echo $i } are not valid expressions. This looks like a mix of a for loop and a Perl syntax. The correct way to write this loop would be:
for file in * do echo $file done
References:
* Looping Statements | Shell Script - GeeksforGeeks
* How do I write a 'for' loop in Bash? - Stack Overflow

問題 #31
Which of the following taroptions handle compression? (Choose two.)

A. -g
B. -bz
C. -j
D. -z2
E. -z

答案：C,E

問題 #32
Which shell variable holds the exit status of the last executed command?

A. `$?`
B. `$0`
C. `$#`
D. `$!`

答案：A

問題 #33
What is true about thedmesgcommand? (Choose two correct answers.)

A. It might not display older information because it was overwritten by newer information.
B. It displays the content of the Linux kernel's ring buffer.
C. It immediately outputs all new messages written to the system journal.
D. It sends messages to the command lines of all current user sessions.
E. It traces the execution of a command and shows each step the program carries out.

答案：A,B

問題 #34
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