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Oracle 1Z1-082 exam, also known as the Oracle Database Administration I exam, is designed for individuals who want to become certified database administrators on Oracle Database 19c. 1Z1-082 exam is the first step towards becoming an Oracle Certified Professional, which is a highly sought-after certification in the IT industry. 1Z1-082 Exam Tests the candidate's knowledge and skills in various areas such as installation, configuration, backup and recovery, database security, and network administration.

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Oracle 1Z1-082 exam is a proctored exam that consists of 80 multiple-choice questions. Candidates have 2 hours to complete the exam and must score a minimum of 64% to pass. 1Z1-082 exam fee is $245, and it can be taken at any Oracle testing center or online through Pearson VUE. Passing 1Z1-082 exam demonstrates that the candidate has a fundamental understanding of Oracle Database Administration and is capable of performing basic tasks related to database management. It also provides a strong foundation for further Oracle certifications.

Oracle 1Z0-082 (Oracle Database Administration I) Certification Exam is a widely recognized certification in the field of database administration. It is designed to test the skills and knowledge of professionals who are responsible for administering Oracle databases. Passing 1Z1-082 Exam is a great way to demonstrate your expertise in Oracle database administration and enhance your career prospects.

Oracle Database Administration I Sample Questions (Q75-Q80):

NEW QUESTION # 75
Which two statements are true about single row functions? (Choose two.)

A. CEIL : can be used for positive and negative numbers
B. TRUNC : can be used with NUMBER and DATE values
C. MOD : returns the quotient of a division operation
D. FLOOR : returns the smallest integer greater than or equal to a specified number
E. CONCAT : can be used to combine any number of values

Answer: B,C

Explanation:
https://docs.oracle.com/en/database/oracle/oracle-database/18/sqlrf/Single-Row- Functions.html#GUID-B93F789D-B486-49FF-B0CD-0C6181C5D85C

NEW QUESTION # 76
Which three statements are true about Oracle synonyms? (Choose three.)

A. Any user can drop a PUBLIC synonym
B. A SEQUENCE can have a synonym
C. A synonym cannot be created for a PL/SQL package
D. A synonym created by one user can refer to an object belonging to another user
E. A synonym can be available to all users

Answer: B,D,E

NEW QUESTION # 77
Which two statements are true about single row functions? (Choose two.)

A. TRUNC : can be used to combine any number of values
B. CEIL : can be used for positive and negative numbers
C. MOD : returns the quotient of a division operation
D. FLOOR : returns the smallest integer greater than or equal to a specified number
E. CONCAT : can be used to combine any number of values

Answer: A,C

NEW QUESTION # 78
Evaluate these commands which execute successfully:

Which two statements are true about the ORD_ITEMS table and the ORD_SEQ sequence? (Choose two.)

A. Any user inserting rows into table ORD_ITEMS must have been granted access to sequence ORD_SEQ
B. Sequence ORD_SEQ is guaranteed not to generate duplicate numbers
C. Sequence ORD_SEQ cycles back to 1 after every 5000 numbers and can cycle 20 times
D. Column ORD_NO gets the next number from sequence ORD_SEQ whenever a row is inserted into ORD_ITEMS and no explicit value is given for ORD_NO
E. If sequence ORD_SEQ is dropped then the default value for column ORD_NO will be NULL for rows inserted into ORD_ITEMS

Answer: A,B

NEW QUESTION # 79
Examine the description of the CUSTOMERS table:

For customers whose income level has a value, you want to display the first name and due amount as 5% of their credit limit. Customers whose due amount is null should not be displayed.
Which query should be used?

A. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNTFROM customersWHERE cust_income_level IS NOT NULLAND cust_credit_limit IS NOT NULL;
B. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNTFROM customersWHERE cust_incoms_level IS NOT NULLAND due_amount IS NOT NULL;
C. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNTFROM customersWHERE cust_income_level <> NULLAND due_amount <> NULL;
D. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNTFROM customersWHERE cust_income_level != NULLAND cust_credit_level !=NULL;
E. SELECT cust_first_name, cust_credit_limit * .05 AS DUE_AMOUNTFROM customersWHERE cust_income_level != NULLAND due_amount !=NULL;

Answer: A

NEW QUESTION # 80
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