Free PDF Quiz 2026 App-Development-with-Swift-Certified-User: Authoritative Test App Development with Swift Certified User Exam Dump

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| Section | Objectives |
|---|
| Xcode Developer Tools | - Use debugging techniques including, but not limited to, breakpoints, watchpoints, and logging to resolve errors
- 1. Set breakpoints and step through code line by line
- Identify and use the features of the Xcode interface
- 1. Navigate Xcode
- 2. Demonstrate how to access documentation and help
- 3. Create and modify views with Interface Builder
- Demonstrate how to build and run an app
- 1. on the iOS device
- 2. on the iOS simulator
|
| Swift Programming Language | - Use functions
- 1. Customize internal, external, and anonymous naming of parameters in functions
- 2. Organize and structure code
- 3. Demonstrate how to use a function's return value
- 4. Implement default parameter values
- 5. Create and call a function
- Declare and use basic Swift types
- 1. Demonstrate when to use constants and variables
- 2. Describe and use data types and operators
- 3. Interpret and use basic types
- 4. Demonstrate the use of type casting in both safe and unsafe ways
- Evaluate variable scope and shadowing - Manage data using collection types - Demonstrate proper use of structs, classes
- 1. Define and use properties and methods
- 2. Differentiate between various initializers
- 3. Differentiate between structures and classes
- 4. Define and use property observers
- Know how and when to apply control flow and loops
- 1. Use Guard
- 2. Use range operators
- 3. Use logical operators
- Demonstrate the use of Optional types
- 1. Apply Optional binding and Optional chaining (including but not limited to if let, guard let)
- 2. Demonstrate how to unwrap Optionals safely
|
| View Building with SwiftUI | - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Create multiple Views to implement app logic - Extract Subviews to simplify the structure of an overlarge View - Use List Views to iterate through collections - Use @State, @Binding, @Environment, and/or Observable to share data between Views - Position and/or layout a single SwiftUI View with standard Views and modifiers
|
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Apple App Development with Swift Certified User Exam Sample Questions (Q38-Q43):
NEW QUESTION # 38
Review the code.
var capitalCities = [ " USA " : " Washington D.C. " , " Spain " : " Madrid " , " Peru " : " Lima " ] Which two statements add the capital city of " Italy " to the dictionary? (Choose 2.)
- A. capitalCities = capitalCities + [ " Italy " : " Rome " ]
- B. capitalCities.updateValue( " Rome " , forKey: " Italy " )
- C. capitalCities[ " Rome " ] = " Italy "
- D. capitalCities[ " Italy " ] = " Rome "
- E. capitalCities.append([ " Italy " : " Rome " ])
Answer: B,D
NEW QUESTION # 39
Review the code snippet.

What value does the code output?
Answer:
Explanation:
Answer the question by typing in the box.
2
Explanation:
This question belongs to Swift Programming Language , specifically the objectives covering functions , control flow , and default parameter values . The function is declared as func getAgeCategory(_ age: Int =
20) - > Int, which means if no argument is supplied, Swift uses the default value 20. Apple's Swift documentation explains that you can define a default value for any parameter, and that value is used when the caller omits that argument. Since the code calls getAgeCategory() with no parameter, the function executes using age = 20.
The conditional logic is then evaluated in order:
* if age > 64 # false, because 20 is not greater than 64
* else if age > 19 # true, because 20 is greater than 19
* so the function returns 2
Because Swift's if / else if control flow stops at the first true condition, the later checks are never reached once age > 19 succeeds. Apple describes Swift as supporting standard control flow including conditional branching, and this example is a direct use of that branching behavior.
Therefore, print(getAgeCategory()) outputs 2 , which corresponds to option B .
NEW QUESTION # 40
Review the code snippet.

What is the output from each print statement?
Answer:
Explanation:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
NEW QUESTION # 41
You need to create a Watchpoint in Xcode. In which order should you complete the actions? Move all the actions to the answer area and place them in the correct order.

Answer:
Explanation:

Explanation:

This question belongs to Xcode Developer Tools , specifically the objective on using debugging techniques including breakpoints, watchpoints, and logging to resolve errors . A watchpoint monitors a variable or memory location during a debugging session, so you first need the program to stop while being debugged.
That is why the correct order begins with setting a breakpoint and then running the code so execution pauses at a useful point. Apple's debugging guidance describes debugging as something done at runtime using the debugger, and LLDB's watchpoint documentation explains that watchpoints are part of the debugger workflow rather than something you set before the program is stopped.
Once execution is paused, you use the debug area to inspect the current variables. After locating the variable you want to monitor, you right-click the variable and select Watch to create the watchpoint. This sequence is consistent with how Xcode and LLDB expose watchpoint functionality during an active debug session.
LLDB also describes watchpoints as objects you create to stop execution when a watched value changes, which only makes sense after the debugger has access to the running program state.
NEW QUESTION # 42
You have created a view which includes some formatted text:

You decide to extract this formatted text into a subview so that you can reuse the formatting for other texts.
You highlight the Text and choose Extract subview.
You refactor ExtractedView to BigGreenTextView.
You add the line let text: String to the extracted view above the body.
You replace " That ' s all folks " with a reference to text
How should you call this extracted View from the original View?
- A. BigGreenTextView( " That ' s all folks " )
- B. BigGreenTextView(text: text)
- C. BigGreenTextView(text)
- D. BigGreenTextView(text: " That ' s all folks " )
Answer: D
Explanation:
This question belongs to View Building with SwiftUI , specifically the domain on extracting subviews to simplify the structure of an overlarge View .
When you create a custom SwiftUI view and add a stored property like:
let text: String
that property becomes part of the view's initializer. Since the property name is text, Swift expects you to pass the value using the parameter label text: when creating the view. So the correct call is:
BigGreenTextView(text: " That ' s all folks " )
That makes B the correct answer.
Why the others are wrong:
* A is incorrect because this is not using the expected parameter label.
* C would only be correct if there were already another variable named text in the calling scope and you wanted to pass that variable instead of the literal string shown in the question.
* D is incorrect because it omits the parameter label.
This is a standard SwiftUI pattern: extract reusable formatting into a separate custom View, give it an input property, and then pass the needed value through the initializer using the property label.
NEW QUESTION # 43
......
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