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| Section | Objectives |
|---|---|
| Topic 1: Swift Programming Language | - Manage data using collection types
- Demonstrate the use of Optional types
|
| Topic 2: Xcode Developer Tools | - Use debugging techniques including, but not limited to, breakpoints, watchpoints, and logging to resolve errors
|
| Topic 3: View Building with SwiftUI | - Use List Views to iterate through collections - Extract Subviews to simplify the structure of an overlarge View - Create a multi-view app with navigation Stacks, Links, and/or Sheets - Create multiple Views to implement app logic - Position and/or layout a single SwiftUI View with standard Views and modifiers - Use @State, @Binding, @Environment, and/or Observable to share data between Views |
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30. Frage
Review the code snippet.
The code snippet does not compile.
Which two actions will fix the errors? (Choose 2.)
Antwort: B,E
Begründung:
This question belongs to Swift Programming Language , especially the domains covering basic Swift types
, operators , and constants versus variables .
There are two compile problems in the snippet. First, unitPrice and shipping are inferred as Double, while quantity is inferred as Int. In Swift, arithmetic operands must have compatible types; Swift does not automatically mix Int and Double in one arithmetic expression. So unitPrice * quantity fails unless quantity is changed to Double or explicitly converted. That makes A a correct fix.
Second, the line totalCost += ... uses the compound assignment operator +=, which stores a new value back into the left-hand side. Swift requires the left-hand side of += to be mutable, so totalCost must be declared with var, not let. That makes D the second correct fix.
The other choices do not solve the actual compile issues. B is unnecessary because totalCost is already explicitly declared as Double, so 0 is valid there. C would still leave shipping as Double, so the mixed-type arithmetic problem remains. E is irrelevant because shipping is never reassigned. Therefore, the two correct answers are A and D
31. Frage
Given the function definition, which two statements call the function correctly? (Choose 2.)
Based on the image provided, here is the text for each of the multiple-choice options:
Antwort: A,C
Begründung:
This question belongs to Swift Programming Language , specifically the objective on functions , including internal and external parameter names and default parameter values .
The function is defined as:
func schedule(who name: String, from starting: String, to ending: String, _ place: String = " Zoom " ) { print( " Appointment: meeting \(name) from \(starting) to \(ending) at \(place) " )
}
This means:
* the external parameter names are who, from, and to
* the internal parameter names are name, starting, and ending
* the last parameter uses _, which means it has no external label
* the last parameter also has a default value of " Zoom "
Now evaluate the options:
* A is incorrect because it uses place: as an external label, but _ place means no external label is allowed.
* B is correct because it uses the required external names who, from, and to, and it omits the last parameter, which is allowed because it has a default value.
* C is incorrect because it uses who:, from:, and to: correctly, but this function's first three parameters are not declared that way in the provided option set; the valid matching call style from the choices is not this one because the function's labels are paired with internal names in the declaration syntax shown in the question.
* D is incorrect because it uses the internal names name, starting, and ending as if they were external labels.
* E is correct because it uses the external labels who, from, and to, and omits the final unlabeled parameter, letting Swift use the default " Zoom " .
So the two correct answers are B and E .
32. Frage
Review the code snippet.
What is the output from each print statement?
Antwort:
Begründung:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
33. Frage
Review the code snippet.
The " faces " dictionary contains emojis and their descriptions.
Which code will create an array named " emo)is " that will copy all the emojis from the " faces " dictionary?
Antwort: A
Begründung:
This question belongs to Swift Programming Language , specifically the objective on managing data using collection types , including dictionaries and arrays . In the dictionary shown, the emojis are the keys and the text descriptions are the values . Swift provides a keys property on dictionaries that returns a collection containing all dictionary keys. To convert that keys collection into an array, you use the Array(...) initializer.
Therefore, the correct code is let emojis = Array(faces.keys). Apple documents both the Dictionary.keys property and the Array type used to store a sequence of values of the same type.
Option B is incorrect because faces.values would return the descriptions like " grinning " , " thinking " , and " happy " , not the emoji keys. Options A and C are incorrect because List is a SwiftUI view type, not the correct collection type for creating an array from dictionary contents. Also, the dictionary interface uses properties like .keys and .values, not method calls like .keys() or .values(). Apple's dictionary documentation makes clear that keys is a property returning a collection of the dictionary's keys.
34. Frage
You need to create a Watchpoint in Xcode. In which order should you complete the actions? Move all the actions to the answer area and place them in the correct order.
Antwort:
Begründung:
Explanation:
This question belongs to Xcode Developer Tools , specifically the objective on using debugging techniques including breakpoints, watchpoints, and logging to resolve errors . A watchpoint monitors a variable or memory location during a debugging session, so you first need the program to stop while being debugged.
That is why the correct order begins with setting a breakpoint and then running the code so execution pauses at a useful point. Apple's debugging guidance describes debugging as something done at runtime using the debugger, and LLDB's watchpoint documentation explains that watchpoints are part of the debugger workflow rather than something you set before the program is stopped.
Once execution is paused, you use the debug area to inspect the current variables. After locating the variable you want to monitor, you right-click the variable and select Watch to create the watchpoint. This sequence is consistent with how Xcode and LLDB expose watchpoint functionality during an active debug session.
LLDB also describes watchpoints as objects you create to stop execution when a watched value changes, which only makes sense after the debugger has access to the running program state.
35. Frage
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