JS-Dev-101 Top Dumps & Online JS-Dev-101 Tests

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| Topic | Details |
|---|
| Topic 1 | - Debugging and Error Handling: Covers proper error handling techniques and the use of the console and breakpoints to debug code.
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| Topic 2 | - Server Side JavaScript: Covers Node.js implementations, CLI commands, core modules, and package management solutions for given scenarios.
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| Topic 3 | - Asynchronous Programming: Covers asynchronous programming concepts and understanding how the event loop controls execution flow and determines outcomes.
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q69-Q74):
NEW QUESTION # 69
Given the requirement to refactor the code above to JavaScript class format, which class definition is correct?

Answer: B
NEW QUESTION # 70
Refer to the code below:
01 funetion Person() (
02 thie. fixsttane = "Zoha'y
os}
05 Perscn.prototype = [
06 jek: x => 'Developer'
onde
09 const myFather = new Peracn():
10 const result = myFather.firstiame + ' * + myFather.jeb()
What is the value of result after line 10 executes?
- A. " John Developer"
- B. Error: myFather.job is not a function
- C. "undefined Developer"
- D. " John undefined"
Answer: A
NEW QUESTION # 71
A developer executes:
document.cookie;
document.cookie = 'key=John Smith';
What is the behavior?
- A. Cookies are read and the key value is set, the remaining cookies are unaffected.
- B. Cookies are read and the key value is set, and all cookies are wiped.
- C. Cookies are read, but the key value is not set because the value is not URL encoded.
- D. Cookies are not read because line 01 should be document.cookies, but the key value is set and all cookies are wiped.
Answer: A
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge document.cookie retrieves the cookie string.
Setting document.cookie = 'key=John Smith' adds or updates only that one cookie.
Important details:
Writing to document.cookie does not overwrite all cookies.
The browser does not require URL encoding, though it is recommended. Non-encoded spaces are allowed and automatically handled.
document.cookies does not exist; the correct property is document.cookie.
Therefore, the correct behavior:
Cookies are read.
A new cookie key=John Smith is set.
Existing cookies remain.
________________________________________
JavaScript Knowledge Reference (text-only)
Writing document.cookie appends or updates cookies, not replaces them.
document.cookie is both getter and setter for cookie strings.
NEW QUESTION # 72
Function to test:
01 const sum3 = (arr) => {
02 if (!arr.length) return 0;
03 if (arr.length === 1) return arr[0];
04 if (arr.length === 2) return arr[0] + arr[1];
05 return arr[0] + arr[1] + arr[2];
06 };
Which two assert statements are valid tests for this function?
- A. console.assert(sum3([0]) === 0);
- B. sum3([0])
- C. console.assert(sum3([1, '2']) == 12);
- D. console.assert(sum3([-3, 2]) === -1);
- E. console.assert(sum3(['hello', 2, 3, 4]) === NaN);
Answer: A,D
Explanation:
Length 1 → returns arr[0] → 0.
Assertion: 0 === 0 → true.
Also a correct and meaningful test.
Therefore, the valid and logically correct tests here are C and D.
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge:
Evaluate each test:
A). sum3([1, '2'])
Array length is 2 → line 4: arr[0] + arr[1] → 1 + '2' → '12' (string).
Assertion: '12' == 12 is true (type coercion).
However, this "test" is not logically correct: a numeric sum function should not be expected to return '12' as a string. It passes only because of weak equality coercion, so it is not a good/valid test of correct behavior.
B). sum3(['hello', 2, 3, 4])
Length ≥ 3 → line 5: 'hello' + 2 + 3 → 'hello2' + 3 → 'hello23'.
'hello23' === NaN is always false because NaN is never equal to anything, not even itself.
This assertion fails and also misunderstands how NaN comparisons work.
C). sum3([-3, 2])
Length 2 → -3 + 2 = -1.
Assertion: -1 === -1 → true.
This is a correct and meaningful test.
NEW QUESTION # 73
Refer to the code below:
Const resolveAfterMilliseconds = (ms) => Promise.resolve (
setTimeout ((=> console.log(ms), ms ));
Const aPromise = await resolveAfterMilliseconds(500);
Const bPromise = await resolveAfterMilliseconds(500);
Await aPromise, wait bPromise;
What is the result of running line 05?
- A. aPromise and bPromise run in parallel.
- B. Neither aPromise or bPromise runs.
- C. Only aPromise runs.
- D. aPromise and bPromise run sequentially.
Answer: B
NEW QUESTION # 74
......
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