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| Section | Weight | Objectives |
|---|---|---|
| Topic 1: Debugging and Error Handling | 7% | - try-catch blocks - Logging strategies and debugging techniques |
| Topic 2: Asynchronous Programming | 13% | - Promises and async/await - Event loop and asynchronous code execution - Callback patterns |
| Topic 3: Objects, Functions, and Classes | 25% | - Higher-order functions and closures - ES6 Classes, constructors, methods, and inheritance - Object creation, properties, and prototypal inheritance - Function declarations, expressions, and arrow functions - JavaScript modules (export, import) |
| Topic 4: Variables, Types, and Collections | 23% | - JSON parsing and stringification - Array manipulation (map, filter, reduce, forEach, find) - Type coercion and type conversion - Variable declaration (var, let, const, scoping, hoisting) - String manipulation and Date objects |
| Topic 5: Server Side JavaScript | 8% | - Modules and file operations - Node.js applications - Salesforce API integration |
| Topic 6: Browser and Events | 17% | - Event handling, propagation, bubbling, and capturing - Browser Developer Tools - DOM manipulation |
| Topic 7: Testing | 7% | - Test-driven development principles - Unit testing with Jest - Automated testing strategies |
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NEW QUESTION # 64
Which two code snippets showworking examples of a recursive function?
Choose 2 answers
Answer: B,C
NEW QUESTION # 65
A developer needs to test this function:
01const sum3 = (arr) => (
02if (!arr.length) return 0,
03if (arr.length === 1) return arr[0],
04if (arr.length === 2) return arr[0]+ arr[1],
05 return arr[0] + arr[1] + arr[2],
06 );
Which two assert statements are valid tests for the function?
Choose 2 answers
Answer: A,B
NEW QUESTION # 66
Refer to the HTML below:
<div id="main">
<ul>
<li>Leo</li>
<li>Tony</li>
<li>Tiger</li>
</ul>
</div>
Which JavaScript statement results in changing "Leo" to "The Lion"?
Answer: D
Explanation:
We want to select the first <li> under #main and change its content.
document.querySelector(selector) returns the first element matching the CSS selector.
In the DOM, the <li> elements under <ul> are children in order:
1st child: "Leo"
2nd child: "Tony"
3rd child: "Tiger"
li:nth-child(1) is the CSS pseudo-class that selects the first <li> inside its parent.
So:
document.querySelector('#main li:nth-child(1)').innerHTML = 'The Lion'; selects the first <li> ("Leo") inside #main and sets its innerHTML to "The Lion".
Why others are incorrect:
A . #main #Leo
There is no element with id "Leo". id is not set on the <li>, so the selector matches nothing.
B . li:second-child
There is no :second-child pseudo-class. The valid pseudo-class is :nth-child(2); and that would select "Tony", not "Leo".
C . '#main li,Leo'
This selector means "all #main li and all elements named <Leo>".
There is no <Leo> tag, and querySelectorAll returns a NodeList, which does not have a single innerHTML property.
Therefore, D is the correct statement.
Study Guide Concepts:
document.querySelector vs querySelectorAll
CSS selectors: nth-child()
DOM element innerHTML property
NEW QUESTION # 67
Refer to the code:
01 function execute() {
02 return new Promise((resolve, reject) => reject());
03 }
04 let promise = execute();
05
06 promise
07 .then(() => console.log('Resolved1'))
08 .then(() => console.log('Resolved2'))
09 .then(() => console.log('Resolved3'))
10 .catch(() => console.log('Rejected'))
11 .then(() => console.log('Resolved4'));
What is the result when the Promise in the execute function is rejected?
Answer: D
Explanation:
execute() returns a Promise that immediately calls reject().
So promise starts in a rejected state.
When a Promise is rejected and you chain .then() calls without rejection handlers, all those .then() callbacks are skipped until a .catch() is encountered:
promise
.then(...) // skipped
.then(...) // skipped
.then(...) // skipped
.catch(...) // executed
.then(...); // executed after catch
Execution:
.then(() => console.log('Resolved1')) is skipped.
.then(() => console.log('Resolved2')) is skipped.
.then(() => console.log('Resolved3')) is skipped.
.catch(() => console.log('Rejected')) runs and logs Rejected.
The .catch() returns a resolved Promise (no explicit return, so undefined), so the next .then() runs:
.then(() => console.log('Resolved4')) logs Resolved4.
Final output:
Rejected
Resolved4
This matches option D.
NEW QUESTION # 68
Refer to the code:
01 const exec = (item, delay) =>
02 new Promise(resolve => setTimeout(() => resolve(item), delay));
03
04 async function runParallel() {
05 const [result1, result2, result3] = await Promise.all(
06 [exec('x', '100'), exec('y', '500'), exec('z', '100')]
07 );
08 return `parallel is done: ${result1}${result2}${result3}`;
09 }
Which two statements correctly execute runParallel()?
Answer: A,C
Explanation:
________________________________________
Comprehensive and Detailed Explanation From Exact Extract JavaScript Knowledge Facts about JavaScript Promises:
runParallel() is declared async, which means it always returns a Promise.
Promises are consumed using .then(), .catch(), and .finally().
There is no .done() method in native JavaScript Promises.
The async keyword cannot be placed before a function call (option A is invalid syntax).
Analysis of each option:
A . async runParallel().then(data);
Invalid syntax. async cannot prefix an expression.
B . Valid. Calls the function and attaches a .then() handler.
C . Invalid. .done() is not part of JavaScript Promise API.
D . Valid. Calls runParallel() and chains .then().
Therefore the correct answers are B and D.
________________________________________
JavaScript Knowledge Reference (text-only)
async functions return Promises.
Promises use .then() to retrieve resolved values.
.done() is not part of the standard Promise interface.
NEW QUESTION # 69
......
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