1z0-071 Test Labs - Associate 1z0-071 Level Exam

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Oracle 1z1-071 exam consists of 73 multiple-choice questions, and the time allotted for completion is two hours. 1z0-071 Exam covers a wide range of topics, including SQL data retrieval, manipulation, and reporting, as well as database objects and structures, data integrity, and transactions.

Preparing for the Oracle 1z1-071 certification exam requires a strong understanding of SQL concepts and principles. Candidates should have experience working with Oracle databases and be familiar with SQL syntax and commands. There are many resources available to help candidates prepare for the exam, including study guides, practice exams, and training courses.

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Oracle 1z1-071 (Oracle Database SQL) Certification Exam is designed for individuals who want to demonstrate their expertise in SQL and database management. Oracle Database SQL certification exam is highly regarded in the industry and is recognized globally. Passing 1z0-071 Exam validates an individual's knowledge and skills in SQL, which is essential for any database administrator or developer.

Oracle Database SQL Sample Questions (Q44-Q49):

NEW QUESTION # 44
Which statement is true about transactions?

A. A combination of DDL and DML statements executed in a sequence ending with a COMMITforms a single transaction.
B. A set of Data Manipulation Language (DML) statements executed in a sequence ending with a SAVEPOINTforms a single transaction.
C. A set of DDL statements executed in a sequence ending with a COMMITforms a single transaction.
D. Each Data Definition Language (DDL) statement executed forms a single transaction.

Answer: D

Explanation:
Explanation/Reference:
References:
https://docs.oracle.com/database/121/CNCPT/transact.htm#CNCPT038

NEW QUESTION # 45
Which three statements are true regarding indexes? (Choose three.)

A. An update to a table can result in updates to any or all of the table's indexes
B. A table belonging to one user can have an index that belongs to a different user
C. An update to a table can result in no updates to any of the table's indexes
D. A UNIQUEindex can be altered to be non-unique
E. When a table is dropped and is moved to the RECYCLE BIN, all indexes built on that table are permanently dropped
F. A SELECTstatement can access one or more indices without accessing any tables

Answer: A,C,E

NEW QUESTION # 46
Examine this partial statement:

Which is true?

A. The query can select any number of rows, but the subquery can select only zero rows or one row.
B. Both the query and the subquery can select any number of rows.
C. Both the query and the subquery can select only zero rows or one row.
D. The query can select only zero rows or one row, but the subquery can select any number of rows.

Answer: D

Explanation:
Explanation/Reference: http://dcx.sybase.com/1200/en/dbusage/ug-subquery-s-4318996.html

NEW QUESTION # 47
Examine the structure of the EMPLOYEES table.

There is a parent-child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?

A. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
B. SELECT e.last_name, m.manager_idFROM employees e LEFT OUTER JOIN employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
D. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;

Answer: A

NEW QUESTION # 48
Examine the description of the CUSTOMERS table:

You need to display last names and credit limits of all customers whose last name starts with A or B In lower or upper case, and whose credit limit is below 1000.
Examine this partial query:
SELECT cust_last_nare, cust_credit_limit FROM customers
Which two WHERE conditions give the required result?

A. WHERE (INITCAP(cust_last_name) LIKE 'A%' OR ITITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000
B. WHERE UPPER(cust_last_name) IN ('A%', 'B%') AND cust_credit_limit < 1000:
C. WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND ROUND(cust_credit_limit) < 1000;
D. WHERE (UPPER(cust_last_name) like INITCAP ('A') OR UPPER(cust_last_name) like INITCAP('B')) AND ROUND(cust_credit_limit) < ROUND(1000) ;
E. WHERE UPPER(cust_last_name) BETWEEN UPPER('A%' AND 'B%') AND ROUND(cust_credit_limit) < 1000;

Answer: A,C

Explanation:
The SQL query must find all customers with last names starting with A or B, regardless of case, and a credit limit below 1000:
B . WHERE (INITCAP(cust_last_name) LIKE 'A%' OR INITCAP(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: The INITCAP function initializes the first letter to uppercase for comparison. However, it should be noted that using INITCAP is not necessary when using the LIKE operator with a wildcard % following a single character, because it will not correctly filter all last names that start with an upper or lower case A or B.
D . WHERE (UPPER(cust_last_name) LIKE 'A%' OR UPPER(cust_last_name) LIKE 'B%') AND cust_credit_limit < 1000: This correctly filters last names beginning with A or B in any case and includes only those with a credit limit below 1000. The UPPER function is used to convert cust_last_name to uppercase before comparison.
Reference:
Oracle Database SQL Language Reference 12c, especially sections on string functions and conditions.

NEW QUESTION # 49
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