H12-811_V2.0 Vce Format | H12-811_V2.0 Exam Passing Score

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Huawei H12-811_V2.0 Exam Syllabus Topics:

TopicDetails
Topic 1
  • Ethernet Technology Basics: Covers Ethernet standards, switching principles, VLANs, and Layer 2 protocols used in enterprise network environments.
Topic 2
  • Data Center Network Basics: Covers the architecture and key technologies used in modern data center networks including virtualization and high-availability design concepts.
Topic 3
  • Network Security and Services: Covers essential network security mechanisms including ACLs, AAA, NAT, and basic firewall concepts to protect network infrastructure.
Topic 4
  • IP Technology Basics: Covers IPv4
  • IPv6 addressing, subnetting, routing fundamentals, and common routing protocols such as OSPF, RIP, and static routing.
Topic 5
  • Data Communication Network Basics: Covers foundational concepts of data communication networks including network types, reference models (OSI
  • TCP-IP), and basic device roles.

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Huawei HCIA-Datacom V2.0 Sample Questions (Q129-Q134):

NEW QUESTION # 129
Which of the following IP addresses cannot be configured for a host by default?

Answer: D

Explanation:
The address 224.0.0.1/24 cannot be configured as a normal host IP address by default because it belongs to the Class D multicast address range . IPv4 multicast addresses range from 224.0.0.0 to 239.255.255.255 and are reserved for multicast group communication rather than assignment to host interfaces as ordinary unicast addresses. Therefore, option D is correct.
The other three options are all private unicast address ranges and can be configured on hosts in private networks. 10.0.0.1/8 belongs to the 10.0.0.0/8 private range, 172.16.1.1/16 belongs to the 172.16.0.0/12 private range, and 192.168.1.1/24 belongs to the 192.168.0.0/16 private range. These are commonly used in enterprise and campus networks. HCIA-Datacom teaches that host IP address planning must distinguish between unicast, multicast, loopback, broadcast, and other special-purpose ranges. Multicast addresses identify multicast groups and are processed differently by hosts and network devices, so they are not valid default host addresses for ordinary end-to-end IP communication.


NEW QUESTION # 130
What is the broadcast address of the network that contains a host with IP address 192.168.1.147/28?

Answer: A

Explanation:
A /28 subnet mask corresponds to 255.255.255.240, which means each subnet contains 16 IP addresses . The subnet boundaries in the last octet increase in steps of 16: 0, 16, 32, 48, 64, 80, 96, 112, 128, 144, 160, and so on. The host address 192.168.1.147 falls within the subnet range 192.168.1.144 to 192.168.1.159 .
In that subnet, the network address is 192.168.1.144, the usable host range is 192.168.1.145 through
192.168.1.158, and the broadcast address is 192.168.1.159. Therefore, option C is correct. Option D is the first usable host address, not the broadcast address. Option A is just another usable host address. Option B would be the broadcast address only for a /24 network, not for a /28. HCIA-Datacom requires learners to master subnetting because it is essential for IP planning, gateway deployment, route summarization, and troubleshooting Layer 3 communication issues in campus and enterprise networks.


NEW QUESTION # 131
The figure shows the simplified topology of an enterprise campus network. On this network, the aging time of dynamic MAC address entries on switches is 300 seconds. The administrator connects PC1 to GE1/0/1 of SW1, and PC2 successfully pings the IP address of PC1. The administrator disconnects the Ethernet cable of PC1 from GE1/0/1 of SW1, immediately connects the cable to GE1/0/2 of SW1, and connects GE1/0/1 of SW1 to another switch. Then, the administrator pings the IP address of PC1 from PC2. In this case, SW1 discards the data frame received from PC2.

Answer: A

Explanation:
Before PC1 is moved, PC2 successfully communicates with it, so SW1 learns PC1 ' s MAC address on GE1/0
/1. The dynamic MAC aging time is 300 seconds, and the cable move is performed immediately. Therefore, when PC2 sends the next frame to PC1, SW1 can still have the old destination MAC entry pointing to GE1/0
/1. The question then states that GE1/0/1 is connected to another switch, so the port remains physically usable.
SW1 follows the existing MAC table entry and forwards the frame out GE1/0/1 toward that new connection; it does not simply discard the frame. If PC1 subsequently transmits from GE1/0/2, SW1 can relearn the same source MAC on the new interface and update the entry, restoring correct forwarding. The core point is that dynamic MAC entries do not immediately disappear merely because the end station is physically moved when the original interface remains Up. Accordingly, the statement that SW1 discards the frame is FALSE, option B.


NEW QUESTION # 132
DAD enables a node to detect whether an IPv6 address is already in use by another node before assigning it to an interface. This ensures that duplicate unicast addresses do not exist on a network. Which of the following packets are used for DAD? (Select all that apply)

Answer: A,D

Explanation:
Duplicate Address Detection (DAD) is an IPv6 mechanism used to verify that a unicast address is not already in use before the address is assigned to an interface. DAD is implemented using Neighbor Solicitation (NS) and Neighbor Advertisement (NA) messages, which are part of the ICMPv6 Neighbor Discovery protocol.
Therefore, options A and D are correct.
When a host wants to verify a tentative IPv6 address, it sends an NS message for that address. If another node on the link is already using that address, that node responds with an NA message, indicating the address is duplicated and cannot be assigned. If no NA is received within the required period, the host assumes the address is unique and can use it. Options B and C are incorrect because Router Solicitation (RS) and Router Advertisement (RA) are used for router discovery, prefix advertisement, and stateless address autoconfiguration, not for DAD itself. HCIA-Datacom emphasizes the distinction between Neighbor Discovery functions, including address resolution, next-hop reachability, router discovery, and duplicate address detection in IPv6 networks.


NEW QUESTION # 133
An IPv6 address is 128 bits long and typically represented in hexadecimal notation, for example,
2001:0001:0DB8:2345:CD30:1230:4567:89AB:CDEF.

Answer: B

Explanation:
An IPv6 address is 128 bits in length and is represented in hexadecimal format, typically written as eight groups of four hexadecimal digits separated by colons. The example given follows the correct IPv6 representation format, so the statement is correct.


NEW QUESTION # 134
......

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